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natulia [17]
1 year ago
14

A job applicant estimates that his chance of passing a qualifying examination is , and his chance of being appointed if he does

pass is . what is the probability that he will receive the job?
Mathematics
1 answer:
Brilliant_brown [7]1 year ago
3 0

The probability that he will receive the job will be 1 / 6

The complete question is given below:-

A job applicant estimates that his chance of passing a qualifying examination is 2/3, and his chance of being appointed if he does pass is 1/4. What is the probability that he will receive the job?

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

It is given that:

The chance of passing a qualifying examination is 2/3=P

and chance of being appointed, if he does pass, is 1/4=P'

Now, we are asked to find the probability that he will receive the job.

We are asked to find the probability that he will receive the job.

The probability is calculated as The probability that he qualify the exam×Probability that he is being appointed.

=P×P'

=(2/3)×(1/4)

=1/6

Therefore the probability that he will receive the job will be 1 / 6

To know more about probability follow

brainly.com/question/24756209

#SPJ1

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Answer:

F=0 or (7/3)

Step-by-step explanation:

When F is 0, the equation reads -0(3(0)-7)=0. The outside 0 will multiply by everything and make it equal 0. When F is 7/3, the inside of the parenthesis read 3(7/3)-7. This equals 7-7. It'll end up being (7/3)0, which equals 0.

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If 4C + 3 = 15, what is the value of C?
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4c+3=15
You need to get rid of the 3
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4c=12
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The ratios of the Areas
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Find the distance between the points R(0,5) and S(12,3). round the answer to the nearest tenth
Burka [1]
12.2

((12) - (0))^2 + ((3) - (5))^2



    
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3 years ago
F(x)=x-1/x^2-x-6 which is the graph of
hoa [83]

Answer:

The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

f\left(x\right)=x-\frac{1}{x^2}-x-6

x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:

\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0

-\frac{1}{x^2}-6=0

-1-6x^2=0

\mathrm{No\:Solution\:for}\:x\in \mathbb{R}

\mathrm{No\:x-axis\:interception\:points}

y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:

y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}

\mathrm{No\:y-axis\:interception\:point}

\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6

\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)

The graph is attached below.

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3 years ago
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