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enot [183]
3 years ago
5

Tell you what (since some of y’all wanna lurk), imma start speaking your language. I’ll give 61 points to whomever can help me o

ut with math. All questions. Not just this one, all questions.

Mathematics
2 answers:
Alla [95]3 years ago
6 0

the first answer is 14

the second answer is 0.2

Ivahew [28]3 years ago
4 0

Answer:

a) 14 hours per dollar b)  1/5 minutes per mile.

Step-by-step explanation:

A)18-4=14

B) 25÷3= 8 125/1000 or 8 1/8

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I dont get this question​ please help meeee
earnstyle [38]
The answer for this is 60
6 0
3 years ago
Someone Please Help!!!
shusha [124]

Answer:

Blue fabric (triangles) = 27 m²

Green fabric (square) = 9 m²

Step-by-step explanation:

✔️Blue fabric (triangles) = 4(area of triangular face)

= 4(½*b*h)

b = 3 m

h = 4.5 m

= 4(½*3*4.5)

= 27 m²

✔️Green fabric (square) = area of the square base

= s²

s = 3

Area = 3²

= 9 m²

8 0
3 years ago
Sven got a $150 gift card function A(n) 150 12.30n gives the amount of money left on the gift card after n number of visits to t
lorasvet [3.4K]

Answers:

1. The n-intercept is 12. That means after 12 visits the amount of money on the gift car is $0.  

2. The A(n)-intercept is 150. Before the visits, the amount of money on the gift car is $150.


Solution:

Amount of money on the gift card after n number of visits: A(n)=$150-$12.50 n

A(n)=150-12.50 n

1. n-intercept

A(n)=0→150-12.50 n =0

Solving for n: Subtracting 150 both sides of the equation:

150-12.50 n-150 = 0-150

-12.50 n = -150

Dividing both sides of the equation by -12.50:

(-12.50 n) / (-12.50) = (-150) / (-12.50)

n=12

The n-intercept is n=12; for n=12→A(12)=0. Point (n, A(n))=(12,0)


2. A(n) intercept

n=0→A(0)=150-12.50 (0)

A(0)=150-0

A(0)=150

The A(n) intercept is 150; for n=0→A(0)=150. Point (n, A(n))=(0,150)

8 0
3 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
Find the horizontal asymptote for each function<br> and tell the reason for your answer.
madreJ [45]

Answer:

Thanks for the free points dear

6 0
3 years ago
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