Answer:
Mitosis is a process of nuclear division in eukaryotic cells that occurs when a parent cell divides to produce two identical daughter cells. During cell division, mitosis refers specifically to the separation of the duplicated genetic material carried in the nucleus.
Explanation:
Make sure to edit so your not copy-writed.
Answer:
3. CABD
Explanation:
The gene mapping refers to providing position to the genes on the chromosomes. The first gene map was constructed by the Alfred Sturtevant on the basis of recombinant produces or recombination frequency which was calculated.
The gene mapping refers to providing position to the genes on the chromosomes.
In the given question to construct gene map:
1. Look for the highest recombination frequency that is 50% between the C and D.
2. Now look for second-highest value and place the gene accordingly.
3.Similarly, place the genes in the decreasing order of recombination frequency and this will result that the sequence of the genes is- CABD.
Thus, Option-3 is correct.
The phenotype of antenna in crawfish depends on the protein amount in the antenna length. The offspring have different phenotype than their parent because of the amount of protein translated from each parent gene is determining in this.
The gene determines the amount of protein to be present in the antenna to determine its length.
Explanation:
Data given:
Two crawfish parent = medium length antennae, genotyoe Ll
One offspring = short antenna, genotype ll
one offspring = long antennae, genotype LL
The traits in offspring is shown as:
L l
L LL Ll
l Ll ll
The proportion of allele present in the gene determined the length of the antenna in crawfish.
The difference in length of the antenna in crawfish is due to the amount of protein for the phenotype present in the individual. The amount of protein to be expressed in the crawfish is given by both the parents. The tendency of protein expresed define the phenotype of antenna length.
Answer:
Alleles for feather colour exhibit incomplete dominance or co-dominance.
50% gray offspring + 50% black offspring
Explanation:
<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>
Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.
Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.
15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.
Bb x Bb = 1BB, 2Bb, and 1bb
Crossing the gray rooster (Bb) with a black hen (bb):
Bb x bb = Bb, Bb, bb, and bb
= 2Bb (gray):2bb (black)
50% of the offspring will be gray while the remaining 50% will be black.
Unfortunately this question is incomplete as it is a multiple choice question. The following options are provided:
<span>A) body cavity between body wall and digestive system
B) number of embryonic tissue layers
C) type of body symmetry
D) presence of Hox genes
E) degree of cephalization
The answer is D: presence of Hox genes
</span>
Hox genes are a group of genes that determine the basic structure and orientation of animals.
