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adoni [48]
2 years ago
7

Find radius of the sphere from the following volume

Mathematics
1 answer:
nordsb [41]2 years ago
3 0
Can you send a picture by chance?
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Damon borrowed money from his grandmother 3 years ago and agreed to pay her 4% simple annual interest. At the end of 3 years, he
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200

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200×4%=8

8×3=24

The original amount is $200

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Write an equation in slope-intercept form with the given slope and y-intercept.
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Step-by-step explanation:

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A trough is 8 feet long and has perpendicular cross section in the shape of an isosceles triangle (point down) with base 1 foot
murzikaleks [220]

Answer:

Dh/dt  = 0.082 ft/min

Step-by-step explanation:

As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of  1 feet and height     h = 2 feet.

The volume of a circular cone is:

V(c)  = 1/3 * π*r²*h

Then differentiating on both sides of the equation we get:

DV(c)/dt   = 1/3* π*r² * Dh/dt   (1)

We know that DV(c) / dt   is  1 ft³ / 5 min      or     1/5  ft³/min

and  we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment

By proportion we know

r/h  ( at the top of the cone  0,5/ 2)   is equal to  r/0.5  when water is 1/2 foot deep

Then      r/h   =   0,5/2   =  r/0.5

r  =  (0,5)*( 0.5) / 2        ⇒   r  =  0,125 ft

Then in equation (1) we got

(1/5) / 1/3* π*r² =  Dh/dt

Dh/dt  = 1/ 5*0.01635

Dh/dt  = 0.082 ft/min

4 0
3 years ago
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