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3 years ago

What is the relationship between multiplying and factoring?

Mathematics

2 answers:

HACTEHA [7]3 years ago

7 0

Answer:

In multiplication the numbers you multiply are called factors; the answer is called the product. In division the number being divided is the dividend, the number that divides it is the divisor, and the answer is the quotient.

Step-by-step explanation:

muminat3 years ago

6 0

Answer:

3x + 12

Step-by-step explanation:

Factoring straddles the line between multiplying and dividing. Let's take a look at the following expression:

3x + 12

Both 3x and 9 have a three in common, so we can factor out that three:

3x ÷ 3 = x

12 ÷ 3 = 4

Now that 3 has been factored out, we set it aside what's left:

3(x + 4)

We can get our original expression by distributing (by multiplying) that 3 back in:

x * 3 = 3x

4 * 3 = 12

You might be interested in

What is the nth term rule of the quadratic sequence below? 7, 14, 23, 34, 47, 62, 79

Julli [10]

Answer:

Tn = Tn-1 + 2(n-1) + 5

Kindly note that Tn-1 means T subscript n-1

Step-by-step explanation:

Here, we want an expression for the nth term.

First term is 7

Then first common difference is 7

second common difference is 7 + 2

Third common difference is 9 + 2

So within the common differences, the nth term is 7 + (n-1) 2

Now, the nth term of the series would be;

Tn = Tn-1 + 7 + 2(n-1)

Tn = Tn-1 + 7 + 2n -2

Tn = Tn-1 + 2n + 5

Now there is a fix to this,

n for the term is not the same n for the common difference.

the 7th term works with the 6th common. difference, while the 8th term work for the 7th common difference.

So we might need to rewrite the final expression as follows;

Tn = Tn-1 + 2(n-1) + 5

6 0

3 years ago

Which expressions are equivalent to 2 (three-fourths x 7) minus 3 (one-half x minus 5)? Check all that apply. -1 29 2 (three-fou

Otrada [13]

The expression is equivalent to $\rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\$ .

<h2 /><h2>Given that</h2>

Expression; $\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)$

<h3>We have to determine</h3>

Which expressions are equivalent to the given expression.

<h3>According to the question</h3>

Expression; $\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)$

To solve the given expression follow all the steps given below.

By applying the distributive property of multiplication;

$\rm a(b+c) = ab+ac$

Then,

The equivalent expression is,

$\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\\
\\
\rm (2 \times \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\
\\
2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\$