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vekshin1
2 years ago
8

Math please help, it is Aleks

Mathematics
1 answer:
yan [13]2 years ago
7 0

Answer:

I can't see properly try a better view of it

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(0,1),(1,3),(2,5),(3,7) function rule
DaniilM [7]

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3 years ago
A cylinder and a cone have congruent heights and radii. What is the ratio of the volume of the cone to the volume of the cylinde
n200080 [17]

A cone with the same radius and height as a cylinder will have one-third the volume of the cylinder.

Vcone = (1/3)*π*r^2*h

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8 0
3 years ago
Solving the following system using the elimination or the substitution method.
Lina20 [59]

Answer and Step-by-step explanation:

For these system of equations, it would be easier to use the substitution method, as we are have one equation that is being equaled to a variable.

Plug the second equation into the value of b for the first equation.

5a + 3(-2a + 3) = 11

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Add together 16 and 3.

19 = b

<u>a = -8</u>

<u>b = 19</u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

5 0
3 years ago
8:10 = 2:5<br> Is a true proportion?<br><br> O Yes<br> O No
Marina86 [1]

Answer:

Step-by-step explanation:

it is not.

7 0
3 years ago
Read 2 more answers
1.) Evaluate the indicated function, where f(x) = x2 − 8x + 3and g(x) = 7x − 5.
noname [10]

Answer:

1) (f + g) (5) = 18, 2) (f + g) (1/2) = - 13/4, 3) (f - g) (-1) = 14, 4) (f * g) (7) = 456, 5) (f/g) (- 2) = - 3/4, 6) (g ○ f)(x) = 6 x - 23, (f ○ g)(x) = 6 x - 6, 7) (g \circ f) (x) = \frac{9}{x} - 24, (f \circ g) (x) = \frac{1}{x - 2} + 5, 8) (f ○ g)(5) = 3

Step-by-step explanation:

1) (f + g) (x) = x^{2}-8\cdot x + 3 + 7 \cdot x - 5\\(f + g) (x) = x^{2} - x - 2\\(f + g) (5) = 18

2) (f + g) (x) = x^{2} - 7 \cdot x + 4 + 6 \cdot x - 7\\(f + g) (x) = x^{2} - x - 3\\(f + g) (\frac{1}{2} ) = - \frac{13}{4}

3) (f - g) (x) = x^{2} - 3 \cdot x + 4 - 4 \cdot x + 2\\(f - g) (x) = x^{2} - 7 \cdot x + 6\\(f - g) (-1) = 14

4) (f \cdot g) (x) = (x^{2}-4\cdot x + 3) \cdot (3\cdot x - 2)\\(f \cdot g) (7) = 456

5) (f / g) (x)  = \frac{x^{2}-3\cdot x + 2}{4 \cdot x - 8} \\(f / g) (-2) = - \frac{3}{4}

6) (g \circ f) (x) = 3 \cdot (2 \cdot x - 8) + 1\\(g \circ f) (x) = 6 \cdot x - 23\\(f \circ g) (x) = 2 \cdot (3 \cdot x + 1) - 8\\(f \circ g) (x) = 6 \cdot x - 6

7) (g \circ f) (x) = 3 \cdot (\frac{3}{x} - 6) - 6\\(g \circ f) (x) = \frac{9}{x} - 24\\(f \circ g) (x) = \frac{3}{3 \cdot x - 6} + 5\\(f \circ g) (x) = \frac{1}{x - 2} + 5

8) (f \circ g) (x) = 2 \cdot (x^{2} - 5 \cdot x) + 3\\(f \circ g) (x) = 2 \cdot x ^{2} - 10 \cdot x + 3\\(f \circ g) (5) = 3

3 0
3 years ago
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