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2 years ago

Solve the following surd given below (1-√5)÷(1+√5)

1 answer:

4 0

$\dfrac{1-\sqrt 5}{1+\sqrt 5}\\\\\\=\dfrac{\left( 1- \sqrt 5\right)\left( 1- \sqrt 5\right)}{\left( 1+ \sqrt 5\right)\left( 1- \sqrt 5\right)}\\\\\\=\dfrac{\left( 1-\sqrt 5)^2}{1^2 - \left(\sqrt 5 \right)^2}\\\\\\=\dfrac{1+\left(\sqrt 5 \right)^2 -2 \sqrt 5\cdot 1}{1-5}\\\\\\=\dfrac{1+5-2\sqrt 5}{-4}\\\\\\=-\dfrac{6-2\sqrt 5}{4}\\\\\\=-\dfrac{2\left(3-\sqrt 5 \right)}{4}\\\\\\=-\dfrac{3-\sqrt 5}{ 2}\\\\\\=\dfrac{\sqrt 5 -3}{2}$

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Enter the value of x that makes the equation 3x + 4 + 2x + 2 = -24

lesya692 [45]

Answer:

x = -6

Step-by-step explanation:

Combine like terms.

5x + 6 = -24

Subtract 6 from both sides.

5x = -30

Divide by 5 on both sides.

x = -6

3 0

2 years ago

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2-1/2 cups water minus 1-2/3 cups water =

weeeeeb [17]

The difference between the mixed numbers is equal to 5/6.

<h3>How to perform the subtraction between the two mixed numbers?</h3>

A mixed number is a number that is written as a whole number plus an improper fraction, here we want to compute:

(2 + 1/2) - (1 + 2/3)

We can group the whole numbers and the fractions, so we get:

(2 - 1) + (1/2 - 2/3)

Now we can simplify this so we get:

(2 - 1) + (1/2 - 2/3)

= 1 + (3/6 - 4/6) = 1 - 1/6 = 6/6 - 1/6 = 5/6

We conclude that the difference between the mixed numbers is equal to 5/6.

If you want to learn more about mixed numbers:

brainly.com/question/1746829

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1 year ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

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11 months ago

a candy factory has to order boxes for its candy canes if they plan to make 300,000 candy canes and each box can hold 12 candy c

natta225 [31]

25,000 boxes should be ordered

Hope this helps and have a good day :D

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3 years ago

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The measure of xy is 124 what is the measure of xyz the tangent chord angle

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