Answer:
46800
Step-by-step explanation:
46821 nearest 100s
look for the tens it is less than 5 so its 800 and the numbers written before the 100s would remain the same
The cost of hiring a car for 2 days in 2013 is Rs. 316.8
<h3>How to find the cost of hiring in 2013 ?</h3>
The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013.
Therefore,
cost of hiring for 2018 = Rs. 264
Therefore,
let
cost of hiring in 2013 = 20%(264) + 264
cost of hiring in 2013 = 20 / 100 × 264 + 264
cost of hiring in 2013 = 1 / 5 × 264 + 264
cost of hiring in 2013 = 264 / 5 + 264
cost of hiring in 2013 = 52.8 + 264
cost of hiring in 2013 = 316.8
Therefore, the cost of hiring a car for 2 days in 2013 is Rs. 316.8.
learn more on cost here: brainly.com/question/1663590
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Step-by-step explanation:
so, just by getting into the taxi we have to pay R10.
that leaves us 22 - 10 = R12 for the actual trip.
30 cents per kilometer.
so, how many units of 30 cents are there in R12 ? that is the number of kilometers we can go.
R12 = 1200 cent (right ?)
1200 / 30 = 120 / 3 = 40
so, we can travel 40 kilometers for that money.
Answer:
$23.27
Step-by-step explanation:
yes
Answer:
False
Step-by-step explanation:
Consider the equations with the same number of equations and variables as shown below,
<u>Case 1</u>
This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.
<u>Case 2</u>
This equation has infinitely many possible solutions.
Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.
