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Readme [11.4K]
2 years ago
13

Pineapples were packed in three large crates. for each crate, the weight of every pineapple in the crate was recorded. here are

three box plots that summarize the weights in each crate. select all of the statements that are true, according to the box plots. (select all that apply. ) the weights of the pineapples in crate 1 were the most variable. the heaviest pineapple was in crate 1. the lightest pineapple was in crate 1. crate 3 had the greatest median weight and the greatest iqr. more than half the pineapples in crate 1 and crate 3 were heavier than the heaviest pineapple in crate 2
Mathematics
1 answer:
IRISSAK [1]2 years ago
5 0
  • The correct statements are:
    the weights of the pineapples in crate 1 were the most variable.
  • The heaviest pineapple was in crate 1.
  • More than half the pineapples in crate 1 and crate 3 were heavier than the heaviest pineapple in crate 2.

<h3>What are the correct statements?</h3>

A box plot is used to study the distribution and level of a set of scores. The box plot consists of whiskers which measure the minimum and maximum numbers. The difference between these numbers is the range which measures variability.

On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile.  The difference between the first quartile and the third quartile is the interquartile range.

For the first box plot:

  • Maximum number = 6
  • Minimum number  = 1.5
  • Range = 6 - 1.5 = 4.5
  • Median  = 4
  • First quartile = 3
  • Third quartile = 4.5
  • IQR = 4.5 - 3 = 1.5

For the second box plot:

  • Maximum number = 3.5
  • Minimum number  = 1
  • Range = 3.5 - 1 = 2.5
  • Median  = 2
  • First quartile = 1
  • Third quartile = 2.5
  • IQR = 2.5 - 1 = 1.5

For the third box plot:

  • Maximum number = 5
  • Minimum number  =2.5
  • Range = 5 - 2.5 = 2.5
  • Median  = 4
  • First quartile = 3.5
  • Third quartile = 4.5
  • IQR = 4.5 -  3.5 = 1

Please find attached the box plots. To learn more about box plots, please check: brainly.com/question/27215146

#SPJ1

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You drive your car for 4.5 hours at an average speed of 70 miles per hour how far did you go
SVEN [57.7K]
In this question, you are given the average speed of the car(70miles per hour) and the time of car travel(4.5 hours). The information is enough to find the car travelling distance. The equation would be:

Distance traveled= average speed * duration= 70miles/h * 4.5 h= 315miles
6 0
3 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals=174174​, x overbarxequals=30.930.9 ​hg, seq
MaRussiya [10]

Answer:

The 95% confidence interval would be given by (29.780;32.020)  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=30.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=7.5 represent the sample standard deviation

n=174 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=174-1=173

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,173)".And we see that t_{\alpha/2}=1.97, this value is similar to the obtained with the normal standard distribution since the sample size is large to approximate the t distribution with the normal distribution.  

Now we have everything in order to replace into formula (1):

30.9-1.97\frac{7.5}{\sqrt{174}}=29.780    

30.9+1.97\frac{7.5}{\sqrt{174}}=32.020

So on this case the 95% confidence interval would be given by (29.780;32.020)    

The value 29.6 is not contained on the interval calculated.

5 0
3 years ago
B) Using the two point above find the slope using the formula m =
12345 [234]

The linear equations are y - 25 = 0.89(x - 20) and y  = 0.89x + 7.2

<h3>The slope of the line</h3>

The complete question is added as an attachment

The two points from the graph are (20, 25) and (38, 41)

The slope of the line is calculated using

m = (y2 - y1)/(x2 - x1)

Substitute the known values in the above equation

m = (41 - 25)/(38 - 20)

Evaluate

m =0.89

<h3>The linear equation in point slope form</h3>

This is calculated as:

y - y1 = m(x - x1)

Substitute the known values in the above equation

y - 25 = 0.89 * (x - 20)

Evaluate

y - 25 = 0.89(x - 20)

<h3>The linear equation in slope-intercept form</h3>

We have:

y - 25 = 0.89(x - 20)

Expand

y - 25 = 0.89x - 17.8

Add 25 to both sides

y  = 0.89x + 7.2

Hence, the linear equations are y - 25 = 0.89(x - 20) and y  = 0.89x + 7.2

Read more about linear equations at:

brainly.com/question/4025726

#SPJ1

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Why can it help to line up the decimal points before comparing and ordering numbers with decimals?
Colt1911 [192]
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Raquel builds a model train that has 4 equal-sized rail cars. Each rail car has a passenger section and a cargo section. The car
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Answer:8

Step-by-step explanation:

48/4 = 12

12-4 = 8

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