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4 years ago

9

movie tickets cost $9.25 each and a large order of popcorn costs $7.75 what is the total cost of 5 movie tickets and a large ord

er of popcorn

2 answers:

Gelneren [198K]4 years ago

8 0

The answer would be 54 dollars

Rainbow [258]4 years ago

3 0

Total Cost Is 54 Dollars.
Here is how you find out.
Because there is 5 tickets, multiply 9.25 by 5 and add 7.75 to get a total of 54 dollars

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dlinn [17]

Answer:

$\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{e^\bigg{\frac{1}{4}}}{8} - \frac{e^\bigg{\frac{1}{9}}}{8}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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Parenthesis
Exponents
Multiplication
Division
Addition
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<u>Algebra I</u>

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Factoring
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<u>Calculus</u>

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f(x) = cxⁿ
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U-Substitution

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Step-by-step explanation:

<u>Step 1: Define</u>

$\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx$

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution.</em>

Set: $\displaystyle u = 4x^{-2}$
[<em>u</em>] Differentiate [Derivative Rule - Basic Power Rule]: $\displaystyle du = -8x^{-3} \ dx$
[<em>du</em>] Rewrite [Exponential Rule - Rewrite]: $\displaystyle du = \frac{-8}{x^3} \ dx$

<u>Step 3: Integrate Pt. 2</u>

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^6_4 {\frac{-8}{x^3}e^{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{1}{9}}_{\frac{1}{4}} {e^u} \, dx$
[Integral] eˣ Integration: $\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{-1}{8}(e^u) \bigg| \limits^{\frac{1}{9}}_{\frac{1}{4}}$
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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

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Answer:

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Answer:

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