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4 years ago

9

movie tickets cost $9.25 each and a large order of popcorn costs $7.75 what is the total cost of 5 movie tickets and a large ord

er of popcorn

2 answers:

Gelneren [198K]4 years ago

8 0

The answer would be 54 dollars

Rainbow [258]4 years ago

3 0

Total Cost Is 54 Dollars.
Here is how you find out.
Because there is 5 tickets, multiply 9.25 by 5 and add 7.75 to get a total of 54 dollars

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How do you graph this function?

kogti [31]

Y= -6 might be the answer idk

5 0

3 years ago

Solve for x 36x-6=16x+18x+2

Elodia [21]

Answer: X=4

Step-by-step explanation:

Pulling out like terms :

1.1 Pull out like factors :

2x - 8 = 2 • (x - 4)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : 2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : x-4 = 0

Add 4 to both sides of the equation :

x = 4

One solution was found :

x = 4

7 0

3 years ago

Can you help me please<br>Find the distance between the points (1,1) and (7,-7)

Vera_Pavlovna [14]

Answer:

10 units

Step-by-step explanation:

to find the distance between two points you will need to use the distance formula:

$\sqrt{(x1-x2)^{2}+(y1 - y2)^{2} }$

the x1 refers to the x coordinate in the first bracket, the x2 refers to the x coordinate in the second bracket, etc.

insert the coordinates into the equation:

$\sqrt{(1 - 7)^{2}+(1--7)^{2} }$

a double negative equals a positive

insert this equation into your calculator:

$\sqrt{(1-7)^{2}+(1+7)^{2} }$ = 10

∴ the distance between the points (1,1) and (7,-7) are 10 units

I hope this was helpful :-)

5 0

3 years ago

How do I even start this? And how to i order the equation to solve

Kobotan [32]

$f(g(h(x)))=f(g(\sqrt x))=f(\sqrt x-1)=\boxed{(\sqrt x-1)^4+4}$

This is because

$h(x)=\sqrt x$

$g(x)=x-1$

$\implies g(h(x))=\sqrt x-1$

(that is, replace any instance of <em>x</em> in the definition of <em>g</em> with √<em>x</em> )

and

$f(x)=x^4+4$

$\implies f(\sqrt x-1)=(\sqrt x-1)^4+4$

(replace any <em>x</em> in <em>f</em> with √<em>x</em> - 1)

Also acceptable:

$(\sqrt x-1)^4+4=((\sqrt x)^4-4(\sqrt x)^3+6(\sqrt x)^2-4\sqrt x+1)+4$

$=\boxed{x^2-4x\sqrt x+6x-4\sqrt x+5}$

(assuming <em>x</em> is not negative)

6 0

3 years ago

X plus three and one sixth equals one and five sixths

Whitepunk [10]

X + 3 1/6 = 1 5/6

*subtract 3 1/6 from both sides

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x = 11/6 - 19/6

x = -8/6

x = -1 2/6

x = -1 1/3

4 0

3 years ago