Answer:
Hi
Step-by-step explanation:
The answer is B and D.
Hope it's correct.
Answer:
x=14
Step-by-step explanation:
<span><span>−<span>5x</span></span>−<span>15y</span></span>−<span>5 is what i get</span>
Answer:
Step-by-step explanation:
Here a equation of the line is given to us and we need to find out the equation of line which passes through the given point and parallel to the given line , the given equation is ,
Firstly convert it into <em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>c</em><em>e</em><em>p</em><em>t</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em> </em>of the line which is <u>y</u><u> </u><u>=</u><u> </u><u>m</u><u>x</u><u> </u><u>+</u><u> </u><u>x</u><u> </u>, as ;
On comparing it to <em>y</em><em> </em><em>=</em><em> </em><em>m</em><em>x</em><em> </em><em>+</em><em> </em><em>c</em><em> </em>, we have ,
Now as we know that the <em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>w</em><em>o</em><em> </em><em>p</em><em>a</em><em>r</em><em>a</em><em>l</em><em>l</em><em>e</em><em>l</em><em> </em><em>l</em><em>i</em><em>n</em><em>e</em><em>s</em><em> </em><em>i</em><em>s</em><em> </em><em>s</em><em>a</em><em>m</em><em>e</em><em> </em>. Therefore the slope of the parallel line will be ,
Now we may use <em>p</em><em>o</em><em>i</em><em>n</em><em>t</em><em> </em><em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em> </em>of the line as ,
On substituting the respective values ,
Again the equation can be rewritten as ,

The polynomial

may have solutions which are the divisors of -20, therefore -20 has the following divisors:

.
If x=1, then

,
if x=-1, then

,
if x=2, then

, then x=2 is a solution and you have the first factor (x-2).
If x=-2, then

, then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of

, then the polynomial

is a divisor of

and dividing the polynomial

by

you obtain

.