The hand went around 7 numbers.
First, let's convert each line to slope-intercept form to better see the slopes.
Isolate the y variable for each equation.
2x + 6y = -12
Subtract 2x from both sides.
6y = -12 - 2x
Divide both sides by 6.
y = -2 - 1/3x
Rearrange.
y = -1/3x - 2
Line b:
2y = 3x - 10
Divide both sides by 2.
y = 1.5x - 5
Line c:
3x - 2y = -4
Add 2y to both sides.
3x = -4 + 2y
Add 4 to both sides.
2y = 3x + 4
Divide both sides by 2.
y = 1.5x + 2
Now, let's compare our new equations:
Line a: y = -1/3x - 2
Line b: y = 1.5x - 5
Line c: y = 1.5x + 2
Now, the rule for parallel and perpendicular lines is as follows:
For two lines to be parallel, they must have equal slopes.
For two lines to be perpendicular, one must have the negative reciprocal of the other.
In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.
However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.
<h3><u>B and C are parallel, no perpendicular lines.</u></h3>
Answer:
angles 1, 3, 6, 8 = 142°
angles 2, 4, 5, 7 = 38°
Step-by-step explanation:
Vertical angles and corresponding angles are congruent, as are alternate interior angles. Hence the angles 1, 3, 6, 8 are all congruent:
∠1 = ∠3 = ∠6 = ∠8 = 142°
Each of the remaining angles forms a linear pair with one or another of those, so is its supplement:
∠2 = ∠4 = ∠5 = ∠7 = 180° -142° = 38°
Answer:
your lucky you did have a online lessons earlll
Step-by-step explanation:
The following are the temperatures in °C for the first 14 days of January:
-6, -2.5, 2, 2.5, -0.5, 5, 10, -3, -7, 3, -1, 7, 1, 4.5
The difference between -8 F and 14 F is 22 F.
