Answer:
11.5
Step-by-step explanation:
using Pythagoras theorem
the square of 13 equals the square of 6 and the unknown side
1. Linear Pair Postulate
2. MAngle 3
3.Angle 3
4.Angle Congruence Postulate
Hope this helps!
-Soul
Answer: the perimeter of the larger triangle is 22 units
Step-by-step explanation:
The diagram of both triangles is shown in the attached photo. The isosceles triangles are triangle ABC and triangle DEF
Perimeter of triangle ABC = 11
For an isosceles triangle, the other two sides are equal. If one equal side is x, then the sum of the two equal sides is x+x = 2x
Perimeter of triangle = sum of the lengths of the 3 sides. Therefore,
11 = 5 + 2x
2x = 11-5 = 6
x = 6/2 = 3
The base of the similar triangle is 10. It means that it is 2 times the base of the smaller triangle. That means the scale factor is 2. Therefore,
If the perimeter of the small triangle is 11, the Perimeter of the larger triangle will be 2 × perimeter of the smaller triangle. This becomes
2 × 11 = 22 units.
It can also be determined by adding the length of each side
3×2 + 3×2 + 5×2 = 6+6+10 = 22 units
Answer:
300
Step-by-step explanation:
To get from 120% to 100% you divide by 1.2 360/1.2=300 :)
Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.