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inna [77]
1 year ago
6

Let z = Equals 38 (cos(pi/8) + I sine (cos(pi//8) ) and w = 2 (cos(pi/16) + I sine (pi/16) ) What is the product of zw?

Mathematics
1 answer:
tatuchka [14]1 year ago
8 0

The product of the terms zw is 76{ cos(3π/16)+i sin (3π/16) }.

Given that,

The equation are z = 38[cos(π/8)+i sin(π/8)] and w = 2[cos(π/16)+i sin(π/16)]

We have to find the product of the zw.

<h3>Whatis product?</h3>

Finding the product of two or more numbers in math is done through multiplication. It is a fundamental mathematical operation that is frequently applied in everyday situations. When combining groups of similar sizes, we use multiplication.

Take the equation,

zw= (38[cos(π/8)+i sin(π/8)])×(2[cos(π/16)+i sin(π/16)])

zw=(38×2){Cos(π/8+π/16)+i sin(π/8+π/16)}

zw= 76{ cos(3π/16)+i sin (3π/16) }

Therefore, the product of the terms zw is 76{ cos(3π/16)+i sin (3π/16) }.

To learn more about product visit: brainly.com/question/2690441

#SPJ4

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