Options for the attached image: - JL - LJ - KJ

Hoochie [10]

Answer:

V ≈ 5575.28

Step-by-step explanation:

First, you will get the radius and in order to get the radius you have to divide 22/2 which will give you 11 then you will plug 11 into the formula which is V= 4/3 pi r^3 then it will come out as this V=4/3 pi 11^3 and if you plug that into the calculator it will give you an answer of 5575.28.

6 0

2 years ago

What expression shows the relationship between the value of any term and n, its position in the sequence for the given sequence?

san4es73 [151]

Answer:

a(n)=3+(n-1)2

Step-by-step explanation:

a(n)=3+(n-1)2

arithmetic sequence

5 0

3 years ago

A quadratic equation is shown below:

Valentin [98]

Part A)

The given equation is:

$25 x^{2} +10x+1=0$

The radicand or discriminant(d) of the equation will be:

$d=(10)^{2}-4(25)(1) \\ \\ 
d=100-100 \\ \\ 
d=0$

Since the discriminant is equal to 0, the given quadratic equation has only 1 root. In other words we can say the the given equation is a perfect square.

Part B)

The given equation is:

$4 x^{2} -4x+1=0$

We can solve this expression by factorization. Factors of middle term are to be made in such a way that their product equals the product of first and third term and sum is equal to the middle term i.e. product should be 4x² and sum should be -4x.
So the two such terms are -2x and -2x. Using the factors and simplifying the equation by taking common we get:

$4 x^{2} -2x-2x+1=0 \\ \\ 
2x(2x-1)-1(2x-1)=0 \\ \\ 
(2x-1)(2x-1)=0 \\ \\ 
(2x-1) ^{2}=0 \\ \\ 
2x-1=0 \\ \\ 
x= \frac{1}{2}$

4 0

3 years ago

How would you solve this? help.

Eddi Din [679]

Answer:

Center: (3,3)

Radius: $2\sqrt{5}$

Step-by-step explanation:

Midpoint and Distance Between two Points

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The distance between both points is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

$\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3$