The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?

we know that

The area of a trapezoid is given by the formula

$A=\frac{1}{2}(b_1+b_2)h$

where

b_1 and b-2 are the parallel sides

h is the height of the trapezoid (perpendicular distance between the parallel sides)

we have

$h=1\ in\\b_1=1\ in\\b_2=3\ in$

substitute the given values in the formula

$A=\frac{1}{2}(1+3)(1)$

$A=2\ in^2$

8 0

3 years ago

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Solve the inequality 5 + 1/x > 16/x

sladkih [1.3K]

Answer:

x < 0 or x > 3

Explanation:

6 0

2 years ago

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Through: (3, -2) and (0, -5) What is the slope

sergij07 [2.7K]

Slope=change in y/change in x (y2-y1/x2-x1)

Slope=-2-(-5)/3-0=3/3=1

answer: slope=1

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3 years ago

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Find the slope of a line that passes through points (-2,1) and (3,-5)

klasskru [66]

Answer:

-1.2

Step-by-step explanation:

4 0

2 years ago

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