Redo !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! the problem is in the imaage

PLS HELP DUE TODAY

Gekata [30.6K]

Here we go !!

Since it's a regular pentagon, all it's sides are equal so let's solve for x

$\hookrightarrow \: 3(x - 1) = 5x - 6$

$\hookrightarrow \: 3x - 3 = 5x - 6$

$\hookrightarrow \: 3x - 5x = - 6 + 3$

$\hookrightarrow \: - 2x = - 3$

$\hookrightarrow \: x = \dfrac{ - 3}{ - 2}$

$\boxed{\boxed{x = \dfrac{3}{2} }}$

now let's find the measure of each side, i.e

$\hookrightarrow \: 5x - 6$

$\hookrightarrow \: (5 \times \dfrac{3}{2}) - 6$

$\hookrightarrow \: \dfrac{15}{2} - 6$

$\hookrightarrow \: 7.5 - 6$

$\mathrm{\hookrightarrow \: 1.5 \: units}$

perimeter = 5 × side length ( for a regular pentagon )

$\hookrightarrow \: 1.5 \times 5$

$\boxed{ \boxed{ \: \: \: \: \: \: \: \: 7.5 \: \: units \: \: \: \: \: \: \: }}$

6 0

2 years ago

URGENT. <br>Q) 18, 19, 20

notsponge [240]

18. s = 5r^2 + 7......making r the subject
s - 7 = 5r^2
(s - 7) / 5 = r^2...by taking the sqrt of both sides, it eliminates the ^2
( sqrt (s-7)/5) = r

19. h = ut - 1/2gt^2....u = 100, t = 1 4/5(or 9/5)...g = 6.4
h = (100)(9/5) - 1/2(6.4)(9/5^2)
h = 180 - 1/2(6.4)(3.24)
h = 180 - 3.2(3.24)
h = 180 - 10.368
h = 169.632 or 169 79/125

20. sorry..do not know this one

4 0

2 years ago

Read 2 more answers

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

2 years ago

If X = 2 centimeters, Y = 6 centimeters, and Z = 6 centimeters, what is the area of the object?

Sedbober [7]

In order to answer the question, it's absolutely essential to have
enough of a description of the object to know which of its parts
'X', 'Y', and 'Z' are, and what other parts it may have.

An ideal way to accomplish this would have been for you to include the
picture that accompanies the question, wherever you copied it from.

4 0

3 years ago

At the same time a 50 ft cell phone tower casts a 32 ft shadow, a near by light pole casts a 20 ft shadow. How tall is the light

White raven [17]

Answer: 31.25 ft

Step-by-step explanation:

50 / 32 = x / 20

32x = 50(20)

x = 31.25 ft

7 0

2 years ago