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1 year ago

your dog gets fed 2/5 of a cup of food each day, your cat gets fed 2/3 of what your dog gets fed, how much do you feed your cat?

Mathematics

1 answer:

konstantin123 [22]1 year ago

8 0

2/3 cup of food = 134g

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Infinite number ends with?

Georgia [21]

Answer:

Infinity never ends. It's more of a concept than a number.

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3 years ago

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How do you solve 5-x=12

Novosadov [1.4K]

5-x=12
Subtract 5 from both sides
-x=7
Divide -1 on both sides so that the only thing remaining is x alone
Final Answer: x= -7

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3 years ago

Jackie won tickets playing the bowling game at the local arcade. The first time, she won 60 tickets. The second time, she won a

Fynjy0 [20]

Answer: i'm pretty sure she got 35 the second time. hope this helps

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3 years ago

A person who is 68in tall casts a shadow that is 54in long. At the same moment, a tree casts a shadow that is 18ft long. What is

34kurt

Answer:

22.67 ft is the height of tree.

Step-by-step explanation:

Given:

Height of a person is 68 in and casts a shadow that is 54 in long.

At the same point, a tree casts a shadow that is 18 ft long.

Now, to find the height of tree.

Let the height of tree be $x.$

If height of a person is 68 in he casts a shadow of 54 in.

So, 68 in is equivalent to 54 in.

Thus, $x$ is equivalent to 18 ft.

Now, to get the height of tree by using cross multiplication method:

$\frac{68}{54} =\frac{x}{18}$

By cross multiplying we get:

$1224=54x$

Dividing both sides by 54 we get:

$22.67=x$

$x=22.67\ ft.$

Therefore, the height of the tree is 22.67 ft.

6 0

3 years ago

A trough is 10 ft long and its ends have the shape of isosceles triangles that are 4 ft across at the top and have a height of 1

Anna11 [10]

Answer:

7.5 ft³/min

Step-by-step explanation:

Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.

Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²

So, V = Ah = 2h = 2(10 - x)

The rate of change of volume is thus

dV/dt = d[2(10 - x)]/dt = -2dx/dt

Since dV/dt = 15 ft³/min,

dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min

Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt

= -dx/dt

= -(-7.5 ft³/min)

= 7.5 ft³/min

And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft

7 0

2 years ago