Hi there!
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I believe your answer is:
(-3, -1) and (1, 3)
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Here’s why:
- I have graphed the two equations given on a graphing program.
- When graphed, they pass at points (-3, -1) and (1,3). Therefore, they are the solutions to the system.
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See the graph attached.
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Hope this helps you. I apologize if it’s incorrect.
Answer:
Below.
Step-by-step explanation:
These are perpendicular line which intersect at (-4, -9).
Vertical line is x = -4.
Horizontal lone is y = -9.
Answer:
3/11
Step-by-step explanation:
Divide both the numerator and denominator by 2.

Y = x² - 3x - 18
When y = 0,
x² - 3x - 18 = 0
<span>(x + 3)(x - 6) = 0
</span>
x = -3 or x = 6
Answer:
Option d
Step-by-step explanation:
given that a, b, c, and d be non-zero real numbers.

we can factorise this equation by grouping

Equate each factor to 0 to get

Ratio of one solution to another would be

So ratio would be ad/bc
Out of the four options given, option d is equal to this
So option d is right