To solve this, first we'll find the area of the rectangle A,
Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A
now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B
finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m
the answer is gonna be a. 5m+40
Hello!
Each time, there will be a 1/2 chance of tossing a head. Therefore, we multiply our two probabilities.
1/2(1/2)=1/4
Therefore, we have a 1/4 or 25% chance of tossing two heads in a row.
I hope this helps!
Answer:
No, it can not be applied.
Step-by-step explanation:
f(x) = 1/x²
f(x) is a polynomial that is not continuous
As,
f(x) = 1/0 is undefines
Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)
Derivative of this function
f'(x) = (1)x^-2
= -2x^(-2-1)
= -2x^(-3)
= -2/x³
= -2/x³
f'(0) = -2/0 is undefined
Thus, mean value theorem can not be applied.
