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Monica [59]
2 years ago
13

PLZ HELP QUICK!! 20pt+

Mathematics
1 answer:
jek_recluse [69]2 years ago
8 0
Q1.

Angle BAD is adjacent to angle CAD

which means they are equal

so angle BAD = 26 degrees


Q2.

Angel BAC = the sum of angles BAD and CAD

because they are adjacent angles

To find the angles we solve the equations

9x-5 = 3x+7

9x-3x = 7+5

6x = 12

x = 12/6

x = 6




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Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.
Sauron [17]

\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

5 0
3 years ago
The number of picces of art at the musem is shown in the table.
densk [106]

Answer:

<u>The solution is multiple:</u>

<u>A. 15 artists with 2 paintings per artist.</u>

<u>B. 10 artists with 3 painting per artist.</u>

<u>C. 6 artists with 5 painting per artist.</u>

<u>D. 5 artists with 6 paintings per artist.</u>

<u>E. 3 artists with 10 paintings per artist.</u>

<u>F. 2 artists with 15 paintings per artist.</u>

Statement and question complete:

The number of pieces of art at a museum is shown in the table.

Oil paintings 30

Photographs 24

Sketches 21.

The museum is hosting a show for July that features the oil paintings and each artist will show more than 1 painting. How many artists could be featured in the show?

Source: https://educationexpert.net/mathematics/929012.html

Step-by-step explanation:

x = Number of paintings per artist

y = Total number of paintings

x ≥ 2

xy = 30

<u>The solution is multiple:</u>

<u>A. 15 artists with 2 paintings per artist.</u>

<u>B. 10 artists with 3 painting per artist.</u>

<u>C. 6 artists with 5 painting per artist.</u>

<u>D. 5 artists with 6 paintings per artist.</u>

<u>E. 3 artists with 10 paintings per artist.</u>

<u>F. 2 artists with 15 paintings per artist.</u>

8 0
3 years ago
HELP I give big brain! See attachment
Makovka662 [10]

Answer:

35

Step-by-step explanation:

Here is the full steps:

Distribute

-7(x+10)=7(5-x)

-7x-70=7(5-x)

Distribute

-7x-70 = 35-7x            → Answer for the attachment "35"

Add 70  to both sides of the equation

-7x-70+70=-7x+35+70

Simplify

-7x=-7x+105

Add 7x  to both sides of the equation

-7x+7x=-7x+105+7x

0 = 105

[RevyBreeze]

7 0
2 years ago
Read 2 more answers
Which expression correctly represents “nine less than the quotient of a number and four, increased by three
Natasha2012 [34]

The required expression is \frac{x}{4}-9+3

Step-by-step explanation:

We need to identify the expression correctly represents “nine less than the quotient of a number and four, increased by three"

Solving:

Let the number is x

The quotient of number and four: \frac{x}{4}

nine less than the quotient of a number and four: \frac{x}{4}-9

Increased by 3 : \frac{x}{4}-9+3

So, nine less than the quotient of a number and four, increased by three is:

\frac{x}{4}-9+3

So, The required expression is \frac{x}{4}-9+3

Keywords: Write algebraic expression from words:

Learn more about Write algebraic expression from words at:

  • brainly.com/question/1600376
  • brainly.com/question/1617787
  • brainly.com/question/9720317

#learnwithBrainly

3 0
3 years ago
How many ohms of resistance are used in the circuit when 15 amperes of current are present? Round your answer to the nearest hun
Olin [163]
The resistance of the circuit, in ohms, is

(the voltage across the circuit) / 15 .
8 0
3 years ago
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