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mezya [45]
3 years ago
9

What is the domain and range of f(x)= |x-6|

Mathematics
1 answer:
marissa [1.9K]3 years ago
7 0
Domain: possible x values
Range: possible y values

Solution: domain: all real numbers
Range: y greater than 0
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An analysis of the decay of 10 grams of an unstable element over time was completed and is displayed in the computer output.
Lady bird [3.3K]

The equation of the least-squared regression line is: In(Element) = 2.305 - 0.101(Time).

<h3>What is a regression line?</h3>

A regression line displays the connection between scattered data points in any set. It shows the relation between the dependent y variable and independent x variables when there is a linear pattern.

According to the given problem,

From the table we can see,

ln(Element) is the dependent variable and Time is the independent variable.

The constant = 2.305,

Time = -0.101

Hence, we can conclude, our least squared regression line will be

In (Element) = 2.305 - 0.101 (Time).

Learn more about regression line here: brainly.com/question/7656407

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6 0
2 years ago
For the following right triangle, find the side length x. Round your answer to the nearest hundredth.
atroni [7]

Answer:

14.97

Step-by-step explanation:

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2 years ago
The y-intercept in the linear equation y = -1/10x – 2 is_[blank]
shtirl [24]
The y - intercept is -2
5 0
3 years ago
Read 2 more answers
This means that each point where the two lines intersect is a
Norma-Jean [14]

Answer: When two or more lines cross each other in a plane, they are called intersecting lines. The intersecting lines share a common point, which exists on all the intersecting lines, and is called the point of intersection. Here, lines P and Q intersect at point O, which is the point of intersection.

I think this the answer‍♀️

8 0
3 years ago
Determine the maximum value of the objective function, P.
Ad libitum [116K]

Answer:

Maximum (250,125) Answer

Step-by-step explanation:

This is more of a graphing problem than it is anything else.

Begin by graphing all 4 given equations.

When you do that, mark the intersection points of at least 2 lines. In this case it is exactly 2 lines for each intersecting point.

6x + 4y <= 2000 and 2x + 4y <= 1000 intersect at (250,125)

x=>0 and y=>0 intersect at (0,0)

6x + 4y <=2000 and x => 0 intersect at 333.333

2x + 4y <=1000 and y>=0 intersect at  0,250.

Any other intersection points fall outside the range of the givens. The shaded part we are interested in is sort of a very dark green/blue. It is the interior of the quadrilateral determined by the 4 vertices that are marked.

Now all you have to do is determine the maximum point using P=15x + 12y

For 0,0                 P = 15*0 + 12,0 = 0

For 0,250            P = 15*0 + 12*250 = 3000

For 333.3333,0   P = 15*333.3333 + 12*0 = 5000 rounded.

For 250,125        P = 15*250 + 12*125 = 5250  Which is the maximum

Answer (250,125) produces the maximum value Answer

5 0
3 years ago
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