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In-s [12.5K]
4 years ago
7

Given the vent diagram below , if a student is randomly selected , what is the probability that he or she is not attending eithe

r college?

Mathematics
1 answer:
Furkat [3]4 years ago
5 0
The correct answer is 28 because all numbers add up to 200 and the number saying that she doesn't attend either is 56, half of 56 is 28. Voila 
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Please help whats the answer !!?
Soloha48 [4]

The correct answer is the one on the top right corner.

3 0
3 years ago
Which choice is correct..Thanks
bija089 [108]
The correct choice is 64 feet
5 0
3 years ago
The Shoes cost $42
svet-max [94.6K]

Answer:

Martha can buy 7 packs of socks.

Step-by-step explanation:

Martha has $53

Shoes = $42

Socks = $1.50 each

First subtract 42 from 53 to figure out how much is left:

⇒ $53 - $42 = $11

then divide the answer by how much each pack of socks cost:

⇒ \frac{11}{1.50} = 7.33

next, take the whole number of the answer and multiply that by $1.50 to figure how much 7 pack of socks cost:

⇒ 7 socks x $1.50 = $10.50

subtract the answer from $11 to figure out how much remains:

⇒ $11 - $10.5 = $0.50

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to the following complex fraction?
ivanzaharov [21]
<h2>Answer:</h2>

The expression which  is equivalent to the following complex fraction is:

                   \dfrac{-2y+5x}{3x-2y}

<h2>Step-by-step explanation:</h2>

We are given a expression in terms of two variables x and y as follows:

\dfrac{\dfrac{-2}{x}+\dfrac{5}{y}}{\dfrac{3}{y}-\dfrac{2}{x}}

Now, on taking least common multiple in the numerator as well as in the denominator we have:

\dfrac{\dfrac{-2y+5x}{xy}}{\dfrac{3x-2y}{xy}}

which on further simplifying is:

\dfrac{-2y+5x}{3x-2y}

5 0
3 years ago
Read 2 more answers
What is k if : k!+48=48((k+1)^m)
lys-0071 [83]

Answer:

The value of k is greater than or equal to 0, i.e. k≥7.

Step-by-step explanation:

The given equation is

k!+48=48((k+1)^m)

The value of k must be a positive integer because k! is defined for k≥0, where k∈Z.

Subtract 48 from both the sides.

k!=48((k+1)^m)-48

k!=48((k+1)^m-1)

k!=48(k+1-1)(\frac{(k+1)^m-1}{(k+1)-1})

Using [\frac{r^m-1}{r-1}=r^{m-1}+r^{m-2}+...+1], we get

k!=48k((k+1)^{m-1}+(k+1)^{m-2}+...+1)

Divide both sides by 48k.

\frac{k!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

\frac{k(k-1)!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

\frac{(k-1)!}{48}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

Note: The value of m can be 0 or 1.

The value of k is positive integer, so the right hand side of the above equation must be a positive integer.

Since RHS of the equation is positive integer, therefore (k-1)! is completely divisible by 48.

k-1\geq 6

Add 1 on both sides.

k\geq 6+1

k\geq 7

Therefore the value of k is greater than or equal to 0.

4 0
4 years ago
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