Nine I believe, because fifth teen divided by five equals three
three times three equals nine.
Answer:
X density = fXpxq and
Y" =InpXq
Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"
fX = In
And PXq =pxq
Thus replacing x with y,
PXq = pyq
(a) Hence the density of Y is FYpyq
(b) at p0, fYpyq =fYp0q= 0
At 5s, FYpyq =5
Just combine like terms: (f+g)(x)=x^2+6x+30
Answer:
from that passage AB+BD=AD ; -4x+50+2x+4=2x+46 so -2x+54=2x+46 ; x=2.
AC=AB+BC ; AB=-4x+50=-4(2)+50=42
the total lengths is AD=2x+46=50
Therefore AC is more than 42 and less than 50 ; you can answer b,c,g