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galina1969 [7]
2 years ago
10

Keiko+has+a+health+insurance+premium+of+$3298+annually. +if+her+employer+pays+90%+of+the+premium,+how+much+does+she+pay+annually

?
Mathematics
2 answers:
alexira [117]2 years ago
8 0

Answer: $329.8

3298-(\frac{90}{100} *3298)\\= 3298 - 2968.2\\= 329.8

soldier1979 [14.2K]2 years ago
5 0

The amount Keiko pays annually is $329.8

To answer the question, we need to know the amount Keiko pays annually

<h3>How to calculate how much Keiko pays annually.</h3>

Since Keiko health insurance premium annually is $3298 and if his employer pays 90% of the premium, we want to know how much Keiko pays.

Since the employer pays 90% of the premium, the employer pays x = 90% of $3298

= 0.9 × 3298

= $2968.2

So, the amount Keiko pays annually is y = premium - amount employer pays, x

= $3298 - $2968.2

= $329.8

So, the amount Keiko pays annually is $329.8

Learn more about insurance premium here:

brainly.com/question/25280754

#SPJ12

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Answer:

30 plus 70 equals 100

Step-by-step explanation:

it tells the gum explicit equation

4 0
3 years ago
"Three times a number increased by eleven is seventeen" translates to which of the following equations?
ololo11 [35]
3x + 11 = 17 i think
7 0
3 years ago
Read 2 more answers
Please help, this makes no sense to me
aev [14]

Answer:

7/11

Step-by-step explanation:

Let X equal the decimal number

Equation 1:

X=0.63¯¯¯¯¯

With 2 digits in the repeating decimal group,

create a second equation by multiplying

both sides by 102 = 100

Equation 2:

100X=63.63¯¯¯¯¯

Subtract equation (1) from equation (2)

100XX99X===63.63...0.63...63

We get

99X=63

Solve for X

X=6399

Find the Greatest Common Factor (GCF) of 63 and 99, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 9,

63÷999÷9=711

Therefore

X=711

In conclusion,

0.63¯¯¯¯¯=711

used

https://www.calculatorsoup.com/calculators/math/decimal-to-fraction-calculator.php

6 0
3 years ago
Brainliest for whoever gets this right
meriva

Answer

14 degrees

Step-by-step explanation:

7 0
3 years ago
The house numbers on the North side of Flynn Street are even. In one block, the house numbers begin 1022, 1032, 1042, 1052. What
Gnom [1K]
The series 1022,1032,1042,1052....

a1=a=1022
d=a2-a1=1032-1022=10
n=5 as 5th term

Sn= a+(n-1)d
= 1022+(5-1)10
= 1022+40
= 1062
Next house will have 1062 as number.
3 0
3 years ago
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