S(t) = sin(πt/6) + cos(πt/6)
Velocity = s'(t) = π/6 (cos(πt/6) - sin(πt/6))
When velocity = 0
cos(πt/6) - sin(πt/6) = 0
cos^2(πt/6) -2cos(πt/6) sin(πt/6) + sin^2(πt/6) = 0
1 - 2cos(πt/6) sin(πt/6) = 0
1 - sin(πt/3) = 0
sin(πt/3) = 1
πt/3 = arcsin(1) = π/2
t = 1.5
acceleration = s''(t) = -(π/6)^2 (cos(πt/6) + sin(πt/6))
s''(1.5) = -(π/6)^2 (cos(π/4) + sin(π/4)) = -(π/6)^2 (2/√2) = -0.3877
accerelation = -0.3877 meter/s^2
Two points give you a line. A third point (often called a check-point) is used to confirm the accuracy of your first two points. If all three line up, you have confirmed you have the correct line.
Answer:
5 is the interquartile range
Step-by-step explanation:
•25th Percentile: 7
•50th Percentile: 8.5
•75th Percentile: 12
•Interquartile Range: 5
Answer:
-1/4 (d+1)< 2
(d+1) × -1 < 2×4
(d+1) × -1 < 8
-d - 1 < 8
-d < 8 + 1
-d < 9
d > -9
d = { -8, -7, -6....., 0, 1, 2, 3, 4,....}
Step-by-step explanation:
brainliest plz
Answer:
2.93
Step-by-step explanation:
