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kari74 [83]
3 years ago
7

Find three consecutive integers such that the sum of the largest and 5 times the smallest is -244. URGENT

Mathematics
1 answer:
Bad White [126]3 years ago
5 0

Answer:

-39+5(-41)=244

Step-by-step explanation:

Consider 3 consecutive integers: (smallest) x, x+1 and x+2 (largest)

Five times the smallest means 5x

Sum of the largest and five times the smallest means x+2+5x

This sum is -244 means x+2+5x=-244

Solve this equation

x+2+5x=-244

6x+2=-244

6x=-244-2

6x=-246

x=-41

So, smallest number is -41, second is -40 and largest is -39

= -39+5(-41)=244

Hope this helps, have a nice day/night! :D

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\bf 8x+13=11x-23\implies 8x+36=11x\implies 36=3x \\\\\\ \cfrac{36}{3}=x\implies \boxed{12=x} \\\\[-0.35em] ~\dotfill\\\\ 2y+12=4y-4\implies 2y+16=4y\implies 16=2y \\\\\\ \cfrac{16}{2}=y\implies \boxed{8=y}


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