Answer:
The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 80 seconds and a standard deviation of 6 seconds.
This means that 
What travel time separates the top 2.5% of the travel times from the rest?
This is the 100 - 2.5 = 97.5th percentile, which is X when Z has a p-value of 0.975, so X when Z = 1.96.




The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.
D= domain = farthest left and right
Domain = (3, infinite)
R = range = bottom to top
Range = (2,2)
Answer:
1.008
1.08
1.6
1.6071
Step-by-step explanation:
least to greatist
Answer:
5n-t/7
Step-by-step explanation:
The product of 5 and n puts them in the same category and product means times and your going to minus t divided by 7
<span>x = 2, y = 1
= 3*2 + 7*1
= 6+7
= 13
Hence, (2, 1) is the answer.</span>