Allen's work is not written properly so I have rearranged it as shown below:
Original problem) –8.3 + 9.2 – 4.4 + 3.7.
Step 1) −8.3 + 9.2 + 4.4 + 3.7 Additive inverse
Step 2) −8.3 + 4.4 + 9.2 + 3.7 Commutative property
Step 3) −8.3 + (4.4 + 9.2 + 3.7) Associative property
Step 4) −8.3 + 17.3
We can see that in step 1), Allen changed -4.4 into +4.4 using additive inverse. Notice that we are simplifying not eliminating -4.4 as we do in solving some equation. Hence using additive inverse is the wrong step.
Alen should have collect negative numbers together and positive numbers together.
Add the respective numbers then proceed to get the answer.
–8.3 + 9.2 – 4.4 + 3.7
= –8.3 – 4.4 + 9.2 + 3.7
= -12.7 + 12.9
= 0.2
Answer:
a =15
b=70
c=400
d=1500
e=5300
Step-by-step explanation:
it will help u
Answer:
1335cm³
Step-by-step explanation:
The question above says that,Krispy kritters cereal used to come in a box with a volume of 2,850 cm3. However, the krispy kritters co. Designed a new larger box 22.5 cm wide, 6.2 cm deep, and 30 cm high and we are now asked to find "How many more cubic centimeters will the new box hold than the old box?
Now we are all aware that the volume of a cube or cuboid(since its a box ) is length multipled by width multiplied by the height.
And we were given the new dimensions which are;
12.5cm wide
6.2cm deep and
30cm high
Apply this given figures in the formula above and we have:
V = 12.5 × 6.2 × 30
= 4185cm³( this is the volume of the box)
Therefore,the difference in volume between the new box and the old box is
4185 - 2850 = 1335cm³
Math is used in construction everywhere.Math is used in construction to measure parts, how many feet, inches, etc. to do and how high to go up.A great example is in the scaling of blueprints, where an architect creates a scale model of the building so that it can fit on paper.
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is 
is correct answer
Therefore ![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2%3D%5Cfrac%7B1%7D%7B3%5E8%7D)
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
( using the property 
)
( using the property 
( combining the like powers )
( using the property 
)
( using the property 
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is is correct answer
