Write the CSS to configure an h1 selector with drop shadow text, a 50%

Write a for loop that will print the values 1 to 20 while skipping the odd numbers (2,4,6,8,10,12,14,16,18,20):

DochEvi [55]

Answer:

void main ( )

{

int counter;

cout<<""Even numbers between 1 to 20 are:""<<endl ;

//Method 1

for (counter = 1; counter <= 20; counter++)

{

if ( counter%2 == 0)

{

cout<<counter<<""\t""<<endl ;

}

//Method 2 – simplest one

for (counter = 2; counter <= 20;)

{

cout<<counter<<""\t""<<endl ;

counter = counter + 2;

}

return 0;

}

Explanation:

In this, Method 1 runs a for loop and check whether each number is divided by 2. If yes, then printed otherwise it is skipped.

In the second method, it runs for loop only for even numbers. This is obtained by incrementing the counter by 2. 

6 0

3 years ago

You have received a Word memo from your supervisor outlining the five-year strategic plan for your company, which operates in a

Maksim231197 [3]

Answer:

The correct option to the following question is C.) Rights Management Services.

Explanation:

The Right Management Services is also referred to as RMS or AD(Active Directory) RMS.

It is the MS Windows security tool which provides us with persistent data protections by enforcing our data access policy.

Our documents are protected with the RMS and the AD RMS, it is an application by which the documents are associated with and be RMS-aware.

It actually called the Windows RMS but its name was changed in MS Windows 2008, RMS to AD RMS.

7 0

4 years ago

In a file-oriented information system, a transaction file ____.

Dima020 [189]

Is it a multiple choice answer?

8 0

3 years ago

JAVAThe method longestStreak is intended to determine the longest substring of consecutive identical characters in the parameter

Butoxors [25]

Answer:

public static void longestStreak(String str){

int maxCharacterCount = 0;

char longestSubString = str.charAt(0);

for(int i=0; i<str.length(); i++){

int currentMaxCharacterCount = 1;

for(int j=i+1; j<str.length(); j++){

if(str.charAt(i) != str.charAt(j)){

break;

}

else {

currentMaxCharacterCount++;

}

if (currentMaxCharacterCount > maxCharacterCount) {

maxCharacterCount = currentMaxCharacterCount;

longestSubString = str.charAt(i);

}

System.out.println(longestSubString + " "+ maxCharacterCount);

}

Explanation:

Let's start from the top of the code and go all the way down.

- Two variables created; maxCharacterCount to count the longest character in the string, and longestSubString to save the current longest substring. Initially they are set to 0 and the first character of given string respectively.

- We need to check all the substrings to find longest one. That is why a nested for loop (for loop inside a for loop) is created.

- The first loop starts from the first character of the given string and goes until the end of the given string.

- Inside the first loop, currentMaxCharacterCount is created to hold the current value of the maximum character in the given string.

- The second loop starts from the second character of the string, and checks if the character is same as the one that is being checked by the first loop.

- If they are not same, then the loop stops.

- If they are the same characters, currentMaxCharacterCount is incremented by 1. (That means we may find our new longest substring)

* Reminder: When the i is equal to 0, j is increasing from 1 to given string length. When i is equal to 1 j is increasing from 2 to given string length and so on. This process repeats for all i and j values to find out the longest substring.

- If currentMaxCharacterCount is greater than maxCharacterCount, that means we have a new longest substring, and maxCharacterCount should be equal to this new substring's count.

- Then, to be able to check for the next possible longest substring, it should continue from the next iteration of the i (longestSubString = str.charAt(i);)

- Finally, when the loops are done checking, longestSubString and maxCharacterCount need to be printed.

5 0

3 years ago

Windows enables each user to establish a _ ,which identifies to windows the resources such as apps and storage locations,a user

guajiro [1.7K]

The only thing I would have been a while ago I have no clue who you want a new song on is that I it is so good to be in

6 0

3 years ago