All categories

2 years ago

Which unit rate is the lowest price per ounce?

Mathematics

2 answers:

Veseljchak [2.6K]2 years ago

3 0

The unit rates are equal

sukhopar [10]2 years ago

3 0

Answer:

Choice B.

Step-by-step explanation:

If you divide $2.49 by 6, you get approximately $0.41(the real answer is 0.415 but cents only go to 2 decimals, so you would cancel out the 5)

If you divide $3.32 by 8, you also get approximately $0.41,

$0.41=$0.41

You might be interested in

Help plz nd thank you<br> (true or false questions)<br> 1.) -19-2+54<12x97+-40<br> 2.) x+1=1+x

Anastaziya [24]

Number one is 33 < 1118 so true and number two is infinite solutions so it would be true as well

6 0

2 years ago

( − 6 u 9 − 14 u 3 ) + ( − 13 u + 2 u 9 )

OverLord2011 [107]

Answer:=−91u

Step-by-step explanation:

5 0

1 year ago

Read 2 more answers

The original sale price of an item at markdowns is $110.95. You have an additional 20% off coupon for markdowns for purchases to

IRINA_888 [86]

Answer:

$22.19

Step-by-step explanation:

20% off the original price = $110.95 - (20% x $110.95)

20% x $110.95 = $22.19

$110.95 - $22.19 = $88.76

difference = $110.95 - $88.76 = $22.19

5 0

2 years ago

Read 2 more answers

The price of an athletic sweatshirt that normally cost $55 goes on sale for 25% off. What is the new selling price of the sweats

Nata [24]

Answer:

Original price: $ 55

Discount percentage: 25 %

Discount: $13.75

Final Price: $41.25

7 0

2 years ago

In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th

olya-2409 [2.1K]

Answer:

$\frac{BE}{EC} =\frac{1}{3}$

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK and Δ EBK are similar

so we have

$\frac{AD}{BE} =\frac{DK}{BK}$

$\frac{AD}{BE} =\frac{4}{1}$

$\frac{BC}{BE}=\frac{4}{1}$ ( ABCD is parallelogram so AD=BC)

$\frac{BE+EC}{BE}=\frac{4}{1}$ ( BC= BE+EC)

$\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}$

$1+\frac{EC}{BE}=4$

$\frac{EC}{BE}=3$ ( subtracting 1 from both side )

$\frac{EC}{BE}=\frac{3}{1}$

taking reciprocal both side

$\frac{BE}{EC} =\frac{1}{3}$

8 0

2 years ago