0.3f +1 = 0.2f - 4.5 What’s the answer step by step

Mathematics

2 answers:

jok3333 [9.3K]2 years ago

7 0

Step-by-step explanation:

.3f+1 = .2f-4.5

1. Subtract .2f both sides

.1f+1 = -4.5

2. Subtract 1 from both sides

.1f = -5.5

3. Divide .1 both sides

f = -55

To check plug in -55 to all the f’s and both sides should be equal.

Hope this helps!

vekshin12 years ago

6 0

Hey!

-----------------------------------------------

Steps To Solve:

0.3f + 1 = 0.2f - 4.5

~Subtract 0.2f to both sides

0.3f + 1 - 0.2f = 0.2f - 4.5 - 0.2f

~Simplify

0.1f + 1 = -4.5

~Subtract 1 to both sides

0.1f + 1 - 1 = -4.5 - 1

~Simplify

0.1f = -5.5

~Divide 0.1 to both sides

0.1f/0.1 = -5.5/0.1

~Simplify

f = -55

-----------------------------------------------

Answer:

$\boxed{ \bf f~=~-55}$

-----------------------------------------------

Hope This Helped! Good Luck!

You might be interested in

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.