![a_1=3;\ a_2=9;\ a_3=15;\ ...\\\\d=a_2-a_1\to d=9-3=6](https://tex.z-dn.net/?f=a_1%3D3%3B%5C%20a_2%3D9%3B%5C%20a_3%3D15%3B%5C%20...%5C%5C%5C%5Cd%3Da_2-a_1%5Cto%20d%3D9-3%3D6)
The formula of the sum of the arithmetic sequence:
![S_n=\dfrac{2a_1+(n-1)d}{2}cdot n](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7B2a_1%2B%28n-1%29d%7D%7B2%7Dcdot%20n)
Substitute:
![a_1=3;\ d=6;\ n=24\\\\S_{24}=\dfrac{2\cdot3+(24-1)\cdot6}{2}\cdot24=(6+23\cdot6)\cdot12=(6+138)\cdot12=144\cdot12=1,728](https://tex.z-dn.net/?f=a_1%3D3%3B%5C%20d%3D6%3B%5C%20n%3D24%5C%5C%5C%5CS_%7B24%7D%3D%5Cdfrac%7B2%5Ccdot3%2B%2824-1%29%5Ccdot6%7D%7B2%7D%5Ccdot24%3D%286%2B23%5Ccdot6%29%5Ccdot12%3D%286%2B138%29%5Ccdot12%3D144%5Ccdot12%3D1%2C728)
Answer:
1,728.
Answer:
9.2
Step-by-step explanation:
first i added 5 + 3 = 8
then i did 1 1/5 + 8=9 1/5
Answer:
The increase is 3/4
75%
Step-by-step explanation:
The answer I believe is the second one to the top
Answer:
By Side-Side-Side (SSS) property, CA = CB
Step-by-step explanation:
Given: /AB/ and bisector /CD/.
Proof: CA = CB
But,
AD = BD (since D is the midpoint of AB)
<CDA = CDB (right angle property)
<CAD = CBA (congruent property of triangles)
Therefore;
Δ ACD = ΔBCD (congruence property)
=
(proportion of the sides of two congruent triangles)
Thus, by Side-Side-Side (SSS) property, CA = CB