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dalvyx [7]
3 years ago
13

True or False: A p is the probability that the results are not due to chance, the probability that the null hypothesis (H0) is f

alse.
Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

False

Step-by-step explanation:?

The hypothesis tests compare weather an event is meant to alter a population mean results, for example, a scientist experiment might have or not have a significant effect over the population results. The test aims to reject the null hypothesis, so what it really want to find out is if the alternative Hypothesis H1 is likely true. The null hypothesis is the probability that the results are not due to chance – if it’s rejected, then the results are due to chance.The level of significance , or so called p-value, is the probability that the null hypothesis (H0) happen , If p is very small then the null hypothesis is rejected - isn’t true- and the alternative Hypothesis is accepted. A higher P value implies a higher probability than results are not happening so that the H0 is accepted and H1 rejected. The null Hypothesis will normally will rejected when the level of significance are either lower than 0.05 or 0.01, the lower P value the higher the level of confidence that the results are due to chance.

Since the first part of the statement (A p is the probability that the results are not due to chance) is correct, and the second part is wrong (…the probability that the null hypothesis (H0) is false), the total statement is false. The correct statement would be as follows : A p is the probability that the results are not due to chance, the probability that the null hypothesis (H0) is true.  

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Step-by-step explanation:

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Andrew lives at an altitude of 135 feet, and his friend Lisa lives at an altitude of -10 feet. blank residence is higher than bl
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You deposit $3000 in an account earning 4% interest compounded continuously. How much will you have in
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Answer: $3,664.21

Formula: A=Pe^{rt}

  • P = principle/original amount = $3000
  • r = rate of interest = 4% = 0.04
  • t = time period (in years) = 5
  • A = the new amount
  • e = Euler's number ≈ 2.718...

Substitute in the values:

A=(3000)e^{(0.04)(5)} =(3000)e^{0.2} =(3000)(1.2214)=3664.208

<u>Approximately $3,664.21</u>

<em>I think this is how you solve it o_O</em>

7 0
3 years ago
When Carson runs the 400 meter dash, his finishing times are normally distributed with a mean of 65 seconds and a standard devia
just olya [345]

Given Information:  

Mean time to finish 400 meter dash  = μ = 65 seconds

Standard deviation to finish 400 meter dash = σ = 2.5 seconds  

Confidence level = 95%

Required Information:  

95% confidence interval = ?

Answer:  

 CI = 60 \: to \: 70 \: seconds

Step-by-step explanation:  

In the normal distribution, the empirical rule states approximately 68% of all the data lie within 1 standard deviation from the mean, approximately 95% of all the data lie within 2 standard deviations from the mean and approximately 99.7% of all the data lie within 3 standard deviations from the mean.

The confidence interval for 95% confidence limit is given by

 CI = \mu \pm 2\sigma

Since approximately 95% of all the data lie within 2 standard deviations from the mean. μ is the mean time Carson takes to finish 400 meter dash and σ is the standard deviation.

 CI = 65 \pm 2(2.5)

 CI = 65 \pm 5

 CI = 65 - 5 \: to \: 65 + 5

CI = 60 \: to \: 70 \: seconds

Therefore, the 95% confidence interval is between 60 to 70 seconds

What does it mean?  

It means that we are 95% confident that the Carson's mean to finish 400 meter dash is within the interval of (60, 70).

4 0
3 years ago
Olivia used her past health history and information about her doctor visits to create this table to compare health costs with an
shusha [124]

The expected value of health care without insurance is $437.25.

The expected value of health care with insurance is $1,636.40.

<h3>What are the expected values?</h3>

The expected values can be determined by multiplying the respective probabilities by its associated costs.

The expected value of health care without insurance

                                                         = (1 x 0) + (0.32 x 1050) + (0.45 x $225)  

                                                         = $437.25

The expected value of health care with insurance

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                                                          = $1,636.40

Thus, The expected value of health care without insurance is $437.25.

         The expected value of health care with insurance is $1,636.40.

Learn more about Expected value from:

brainly.com/question/13945225

#SPJ1

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