subsitute x = 6 into the lengths
3(6) -7
18 - 7
11cm
(6) + 5
11cm
therefore it is a square when x = 6 because the sides are all equal
Travel distance by light in a second = 3*10^5 kms
Travel distance by light in 60 seconds =
3*10^5 * 60
180 * 10^5
1.8 * 10^7 kms
Answer:
x = -33
Step-by-step explanation:
2/3(x+6)=-18
Multiply each side by 3/2
3/2*2/3(x+6)=-18*3/2
x+6 = -27
Subtract 6 from each side
x+6-6 = -27-6
x = -33
Answer:
51.9
Step-by-step explanation:
because one side is 30 and another is 60, you can assume the 3rd side of the triangle is 51.9 because of the 30-60-90 rule which states that if each angle of a triangle is 30, 60, and 90, then the side lengths equal x (30), 2x (60), and x√(3) (~51.9).
Explanation:
All of these are done the same way.
1. Set your compass to a distance slightly longer than the distance from the point to the line you want the perpendicular to.
2. Using the point as a center, draw an arc that intersects the line in 2 places. Consider those points to be "P" and "Q".
3. You can leave the compass as is, or set it to any other distance longer than half the distance between P and Q. Using this radius, and using P and Q as centers, draw intersecting arcs on the other side of the line from the original point. Consider the intersection of those arcs to be point "R".
4. A line through the original point and point R will be perpendicular to the line, as you want.
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In problem 1, the point and line are obvious.
In problem 2, the point is the vertex opposite the line of interest. (There will be 3 similar constructions.)