Let x be the length of the train.
On the basis of the observer;
Speed of the train = x/6
On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20
Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.
Therefore,
Length of train = 150 m
Speed of train = 25 m/s
Answer with explanation:
A triangle is valid triangle if sum of length of two sides is greater than the third side.
Let one side =a = 3 cm
Second side =b = 5 cm
Third Side = c Cm
So, for a valid triangle
1.
a+b > c
3 +5 > c
c < 8 Cm
2.
c+3 > 5
c> 5-3
c>2 Cm
3.
As, 5+c will always be greater than 3.
→→→So, combining 1 and 2 , we get
2 Cm< Third side < 8 Cm, for a valid triangle.
This kind of decimal is called a terminating decimal, meaning it ends rather than repeating on forever like this one: 4.5555555555...... or the fraction 2/3 when you turn it into a decimal.
Time spent is independent and the amount earned is dependent should be number 1
