Simplify 8-(-5) - 4(-7).<br> О-63<br> оо ООО

Trevor says the figure B is a scaled copy of figure 8 because figure B is three times larger than figure A

yanalaym [24]

Answer:

Hi b

Step-by-step explanation:

3 0

2 years ago

Simplify the expression. w - .25w

balandron [24]

Combine like terms.

1w - 0.25w = 0.75w

Hope this helps!

3 0

3 years ago

What is the slope of the line that passes through the points (-4,4) and (-6,6)

ElenaW [278]

The answer is 2/-2
Using the formula y^2-y^1/x^2-x^1

4 0

3 years ago

Read 2 more answers

PLZZ HELP URGENT

Mashcka [7]

Answer:

5x + 2x.....combine like terms..... = 7x

5x + 2x....subbing in 1 7x - 1....subbing in 1

5(1) + 2(1) = 5 + 2 = 7 7(1) - 1 = 7 - 1 = 6

5x + 2x...subbing in 2 7x - 1...subbing in 2

5(2) + 2(2) = 10 + 4 = 14 7(2) - 1 = 14 - 1 = 13

5x + 2x...subbing in 3 7x - 1...subbing in 3

5(3) + 2(3) = 15 + 6 = 21 7(3) - 1 = 21 - 1 = 20

5x + 2x...subbing in 4 7x - 1....subbing in 4

5(4) + 2(4) = 20 + 8 = 28 7(4) - 1 = 28 - 1 = 27

5x + 2x...subbing in 5 7x - 1...subbing in 5

5(5) + 2(5) = 25 + 10 = 35 7(5) - 1 = 35 - 1 = 34

5x + 2x result values are 1 more then 7x - 1 result values

there are no values that will make the 2 expressions equal....

because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago

Simplify 8-(-5) - 4(-7). О-63 оо ООО