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Marina86 [1]
4 years ago
14

Please Help!

Mathematics
1 answer:
Flura [38]4 years ago
8 0
Let x be the length of the train.

On the basis of the observer;
Speed of the train = x/6

On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20

Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.

Therefore,
Length of train = 150 m
Speed of train = 25 m/s
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Note that the formula is: ax² + b(x) + c =0

You are trying to write it in the form: a(x - b)² = c


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Because you are just telling us to write it in the form a(x − b)² = c, 6(x - 12)² = 9

is your answer




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