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Marina86 [1]
3 years ago
14

Please Help!

Mathematics
1 answer:
Flura [38]3 years ago
8 0
Let x be the length of the train.

On the basis of the observer;
Speed of the train = x/6

On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20

Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.

Therefore,
Length of train = 150 m
Speed of train = 25 m/s
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vlabodo [156]

The monthly  payment on the mortgage is option C) $2537.44

<u>Step-by-step explanation</u>:

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Answer:

(x_1,y_1) = (1,5840)

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x = weeks; y = copies

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y_0 = 1812.5*0 + 4027.5

y_0 = 0 + 4027.5

y_0 = 4027.5

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