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1 year ago

Seleccione el número que se puede describir mejor como enteros.

Mathematics

1 answer:

Zielflug [23.3K]1 year ago

7 0

the second one

Step-by-step explanation:

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When a cube with sides numbered one through six is roll one time what is the probability of rolling a four or greater?

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Since it's a six dice then it's out of x/6

How much is 4 to 6 ?

~3 (counting 4) 4.5.6...

So it's 3/6 = 1/2

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What is the answer to this ? 1.39×2

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Answer:

The answer is 2.78

Step-by-step explanation:

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3 years ago

What is not a description of slope?

Gelneren [198K]

Answer:

Option (d) is wrong.

Step-by-step explanation:

Slope is:

rise over run
The rate of change of a line
Change in y over the change in x
The ratio of vertical change to the horizontal change.

It can be given by mathematically as follows :

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{and}\\\\m=\dfrac{dy}{dx}$

Hence, the option which is not a description of slope is (d) "the ratio of horizontal change compared to vertical change"

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3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

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3 years ago

Choose the correct answer to 96 divided by 6

4vir4ik [10]

Answer:

correct answer is 16. hope that helps

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3 years ago

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