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Natali [406]
3 years ago
6

nick loaned 550 to his best friend. the friend agreed to pay it back the amount borrowed plus 12% interest. what was the total a

mount nick's friend had to play
Mathematics
1 answer:
lina2011 [118]3 years ago
3 0
$616 because 550 times .12(12% as decminal) is 66. $66 plus $550 is $616
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Solve the equation, and check the solutions (√x+3)+6=3.
larisa86 [58]

Answer:

The equation has no solution.

Step-by-step explanation:

Hi there!

First, let´s write the equation:

(√x + 3) + 6 = 3

To solve the equation, let´s subtract 6 to both sides of the equation:

√x + 3 = -3

subtract 3 to both sides of the equation:

√x = -6  (the square root of any number can´t be negative, but let´s solve it anyway and then check the solution).

Square both sides of the equation:

x = 36

Now, let´s check the solution:

(√x + 3) + 6 = 3

x = 36

(√36 + 3) + 6 = 3

(6 + 3) + 6 = 3

9 + 6 = 3

15 ≠ 3

Then, the equation has no solution.

Have a nice day!

6 0
2 years ago
How many windows would Carpenter A install in 10 hours?
DerKrebs [107]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
The first term of an arithmetic sequence is -5, and the tenth term is 13. find the common difference
Vilka [71]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
"I'm thinking of a fraction that is equivalent to 5/6
Liono4ka [1.6K]

Answer:

20/24

Step-by-step explanation:

let the variable be x and x-4

5/6 = x-4/x

cross multiply

5x = 6x - 24

24= x

thus, x is 24 and x-4 is 20

<u>20/24</u>

4 0
3 years ago
heather has divided $6300 between two invesments, one paying 9%, the other paying 4%. If the return on her investment is $372, h
Ganezh [65]
Assuming that the two investments are  X & Y
X + Y = 6300
X = 6300 - Y                                       (1)

9/100X + 4/100 Y = 372                       (2)
replacing X from (1) into (2)
9/100(6300-Y) + 4/100 Y = 372
567 - 9/100Y +4/100Y = 372
(-9+4)/100Y = 372 - 567
5/100Y = -195
Y = 100*195/5 = 3900
From (1) we can get X
X = 6300 - 3900 = 2400

I hope this is helpful 



6 0
3 years ago
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