All categories

2 years ago

The solution of the equation 3(p - 5) = 5p -27 is

Mathematics

2 answers:

taurus [48]2 years ago

6 0

3(p-5)=5p-27
3p-15=5p-27
5p-3p=-15+27
2p=12
p=6

inn [45]2 years ago

3 0

Answer:

A) p = 6

Step-by-step explanation:

Given equation:

3(p - 5) = 5p -27

<u />

Apply the <u>Distributive Property of Multiplication over subtraction law</u>:

⇒ 3 · p - 3 · 5 = 5p - 27

⇒ 3p - 15 = 5p - 27

Add 27 to both sides:

⇒ 3p - 15 + 27 = 5p - 27 + 27

⇒ 3p + 12 = 5p

Subtract 3p from both sides:

⇒ 3p - 3p + 12 = 5p - 3p

⇒ 12 = 2p

⇒ 2p = 12

Divide both sides by 2:

⇒ 2p ÷ 2 = 12 ÷ 2

⇒ p = 6

You might be interested in

2 – (–8) + (–3) = ?

vodka [1.7K]

A minus before a parenthesis means we need to change the sign.

So 2 + 8 - 3 = 7

5 0

2 years ago

Modeling with systems of linear inequalities

NeX [460]

Huh what you mean.....

8 0

3 years ago

Complete the following sentences: 7. In 49 is the base and is the exponent. 8.72 is the exponential form of 7*___ Rewrite each o

serg [7]

Answer:

the 4 is the base and the 5 is the exponent

7^2 is the exponential form of 7*7

10^2

5^4

8 0

2 years ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 58.

Yanka [14]

Answer: 0.025

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].

The probability density function :-

$f(x)=\dfrac{1}{58-48}=\dfrac{1}{10}$

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-

$\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025$

Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025

Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025

5 0

2 years ago

A square room has a tiled floor with 81 square tiles. How many tiles are along an edge of the room?

Sladkaya [172]

Answer:

36 tiles

Step-by-step explanation:

Because the room is square, the numbers of tiles along the edge of the room were multiplied by the same number, meaning that:

81 = x²

So to find x, we must square root both sides of the equation:

$\sqrt{81} = \sqrt{x^2}$

x = 9

So the length of one side is 9 tiles. Now to calculate the circumference, as each side of a square is the same length, we can multiply this number by 4:

9 * 4 = 36

So there are 36 tiles along the edge of the room.

Hope this helps!

4 0

2 years ago