Help Pls ima fail school lol

Mathematics

1 answer:

wel3 years ago

6 0

Answer:

See pic

Step-by-step explanation:

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Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.

gulaghasi [49]

This equation is an example of a Limacon with inner loop. By using the symmetry tests where:

POLAR AXIS/HORIZONTAL:
replace a) θ by -θ, b) r by -r and θ by π-θ

VERTICAL AXIS:
replace a) θ by π-θ, b) r by -r and θ by -θ

POLE:
replace a) θ by π+θ, b) r by -r

If any of these rules, after replacing it in the equation, results to the original equation (making it the equivalent) then it is symmetrical to that axis.

In this case, it is only symmetrical about the polar/horizontal axis.

4 0

3 years ago

Read 2 more answers

Solve and check 8-(6-8x) =4x+4

navik [9.2K]

Greetings!

"Solve and check $8-(6-8x)=4x+4$ "...

Solve for x:
 $8-(6-8x)=4x+4$
Remove the Parenthesis.
$8-6-8x=4x+4$
Simplify.
$2-8x=4x+4$
Add -4 to both sides.
$(2-8x)+(-4)=(4x+4)+(-4)$
Simplify.
$-2-8x=4x$
Add 8x to both sides.
$(-2-8x)+8x=(4x)+8x$
Simplify.
$-2=12x$
Divide both sides by 12.
$(-2)/12=(12x)/12$
Simplify.
$-0.166666667=x$

The answer is: x=-0.166666667

Hope this helps.
-Benjamin

7 0

3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$