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Allisa [31]
2 years ago
5

Morning for z-score: evening flight Z score :​

Mathematics
1 answer:
JulsSmile [24]2 years ago
6 0

Answer:

See below

Step-by-step explanation:

Morning flight   mean 15 minutes    SD = 5

   30 minutes late would be    15/5 = 3 SD  below the mean

           z  = 3

Evening    mean  20 minutes    being 10 more minutes late = 10/3 =3.33 below the mean

         z score = 3.33

evening is more late than the AM

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Help me I need help fast it is due soon!
Arte-miy333 [17]

Answer:

400 square meters

Step-by-step explanation:

We can first solve this problem with each unit representing 1 centimeter, and then scale up at the very end. The shape that we have a parallelogram. The base is 8 cm, and the height is 2 cm. The formula for the area of a parallelogram is just bh, so the area of the parallelogram is 16 square centimeters. However, now we scale up. Since each centimeter correlates to 5 meters, each little box will correlate to 25 square meters. Therefore, 16 \cdot 25 = \boxed{400} square meters is our answer

6 0
3 years ago
A trapezoid is 64cm^2. The height is 12 cm and one base is 4cm. What is the length of the missing base?
Debora [2.8K]

Answer:

20/3

Step-by-step

(base1+base2)/2 * height = area of a trapezoid

64/12=16/3

16/3*2 = 32/3

32/3-4 = 20/3

4 0
4 years ago
What is the domain of h?
sergeinik [125]

Answer:

C

Step-by-step explanation:

  • The domain is all the x numbers for each point
  • So -5,-4,0,2,4
3 0
3 years ago
What is the value of y when -5 =<br> = y - 7?<br> 9<br> a. -7<br> b.-11<br> C. -38<br> d. -52
weqwewe [10]

Answer:

2

Step-by-step explanation:

You have to cancel the -7 so you would add +7 to each side.

-7+7=0, -5+7= 2

y=2

Although this isn't an answer choice. Did you mistype something?

8 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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