Prove
m∠5+m∠2+m∠6=180°
we have that
m∠1+m∠2+m∠3=180° equation I
m∠1=m∠5 -------- > in<span>ternal alternate angles equation 2
</span>
and
m∠6=m∠3-------- > internal alternate angles equation 3
<span>I substitute equation 2 and equation 3 in equation I</span>
m∠1+m∠2+m∠3=180°-------- > m∠5+m∠2+m∠6=180°------- > is ok
Answer:
6
Step-by-step explanation:
1/2 = 0.5
2/5 = 0.4
60 × 0.5 = 30
60 × 0.4 = 24
30 + 24 = 54
60 - 54 = <u>6</u>
In the given diagram, the value of x is 90°
<h3>Calculating angles</h3>
From the question, we are to determine the value of x
In the given diagram,
Using the linear pair theorem, we can write that
x + 90° = 180°
x = 180° - 90°
x = 90°
Hence, the value of x is 90°
Learn more on Calculating angles here: brainly.com/question/23988182
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