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jeka57 [31]
2 years ago
13

Which graph represents the function f(x))=2•(1/3)^xm

Mathematics
1 answer:
Tanzania [10]2 years ago
4 0

Answer: the on to the bottom left

Step-by-step explanation: c would be right because you have a positive slope

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Someone help me with this please
dmitriy555 [2]

Answer:

the answer is c=34

Step-by-step explanation:

use the pythogoras therom since there is a right angle triangle c2=a2+b2

hope this helped:)

8 0
2 years ago
Read 2 more answers
25x = 125x + 3<br><br> x = −10<br> x = −9<br> x = −3<br> x = 3
ICE Princess25 [194]

Answer:

x=-9

Step-by-step explanation:

first you make the coefficients equal to each other by doing a common factor which in this case is 5. Then you have to do the variable for each time the common number is repeated which is 5^x * 5^x= 5^(x+3)*5^(x+3)*5^(x+3) This would make it equal to 5^2x=5^(3x+9). Since the non exponents are common factors you can get rid of them and solve for the exponent by doing 2x=3x+9. You solve that equation to get x=-9.

8 0
2 years ago
6x + 5y = 16<br> −6x + 7y = 80
Kobotan [32]

The equation of the line in point-slope form is equal to

The equation of the line in standard form is equal to

step 1

Find the slope m

Let

step 2

convert to standard form

6 0
3 years ago
Solve for |2x+6|=8<br><br><br> Algebra
bearhunter [10]

x=1 or x=−7

Hope this helps :)

7 0
3 years ago
Read 2 more answers
Help and show explanation please
Dennis_Churaev [7]
The picture can be divided into 2 same triangles and one rectangular.

The triangle areas is {1/2 *base * height}*2 (because 2 same triangles)

and you need to sum rectangular area (width * base).
The result will be area of 2 triangle +area of rectangular.
=2(1/2*base of triangle* height)+ (base of rectangular * height)
= (base of triangle* height)+(base of rectangular * height)
=(base of triangle +base of rectangular)*height

b1 is top length
b2 is bottom length, and so

Base of triangle =(b1-b2/2)
Base of rectangular =b2
Height =h
Thus A ={(b1-b2/2)+b2 }*h
A= [(b1+b2)/2]*h
8 0
1 year ago
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