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2 years ago

Given the triangle below choose true or false show work

Mathematics

2 answers:

marysya [2.9K]2 years ago

6 0

True, False, True, False. You're Welcome!

disa [49]2 years ago

5 0

1.True

2.False

3.true

4.false

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Miyoko's goal is to earn more than \$950$950dollar sign, 950 this week. She earns \$250$250dollar sign, 250 for every day she wo

GrogVix [38]

$250 c+ $ 180 g > $ 950

<u>Step-by-step explanation:</u>

As a cryptographer (c), Miyoko earns per day = $ 250

As a geologist (g) , Miyoko earns per day = $ 180

So the equation comes to be $250 c+ $ 180 g = $ 950

The equation can be rewritten to find c as, (950-180 g) / 250

The equation can be rewritten to find g as, (950 - 250 c) / 180

Plugin different values of c and g in the above 2 equations, we can find that ,

To achieve the goal, Miyoko requires to be a geologist for 3 days and crpytographist for 2 days.

5 0

2 years ago

Rewrite the following equation in slope-intercept form. x + 5y = -11 Write your answer using integers, proper fractions, and imp

AveGali [126]

Answer:

$\displaystyle y = -\frac{x}{5} - 2\frac{1}{5}$

Step-by-step explanation:

$\displaystyle x + 5y = -11 → 5y = -x - 11 → \frac{5y}{5} = \frac{-x - 11}{5} \\ \\ y = -\frac{1}{5}x - 2\frac{1}{5}$

I am joyous to assist you at any time.

7 0

2 years ago

Find the value of x from the given figure:

zubka84 [21]

Answer:

60°

Step-by-step explanation:

2x and x are linear pair,

=> 2x + x = 180

=> 3x = 180

=> x = 180/3

=> x = 60°

=>2x =120°

7 0

2 years ago

Read 2 more answers

If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.

harina [27]

Answer:

Step-by-step explanation:

When we simplify we get $z(6xy+21x+2y+7)+30xy+105x+10y=812.$

Then we continue to factor to get: $(z+5)(6xy+21x+2y+7)&=847.$

We then see that we can factor $(6xy+21x+2y+7)$ into $(z+5)(3x+1)(2y+7)&=847.$

we then do the prime factorization of 847, which i think is, $7*11*11$ . we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

8 0

3 years ago

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

alexira [117]

Answer:

Option B

Step-by-step explanation:

Given quadratic equation is,

12a² + 9a + 7 = 0

By comparing this equation with standard quadratic equation,

hx² + kx + c = 0

h = 12, k = 9 and c = 7

By using quadratic formula,

a = $\frac{-k\pm\sqrt{k^2-4hc}}{2h}$

= $\frac{-9\pm\sqrt{9^2-4(12)(7)}}{2(12)}$

= $\frac{-9\pm\sqrt{81-336}}{2(12)}$

= $\frac{-9\pm\sqrt{-255}}{24}$

= $\frac{-9\pm i\sqrt{255}}{24}$

a = $\frac{-9+ i\sqrt{255}}{24},\frac{-9- i\sqrt{255}}{24}$

Therefore, Option B will be the correct option.

3 0

2 years ago