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lorasvet [3.4K]

2 years ago

12

Carmen used a random number generator to simulate a survey of how many children live in the households in her town. There are 1,

346 unique addresses in her town with numbers ranging from zero to five children. The results of 50 randomly generated households are shown below.
Children in 50 Households
Number of Children
Number of Households
0
5
1
11
2
13
3
10
4
9
5
2

Using a proportion, what can you infer about the number of households in her town that have more than three children?
About 242 households have more than three children.
About 269 households have more than three children.
About 296 households have more than three children.
About 565 households have more than three children.

1 answer:

kiruha [24]2 years ago

4 0

About 296 households have more than three children. Then the correct option is C.

<h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

The expected value will be

E(X) = np

Carmen used a random number generator to simulate a survey of how many children live in the households in her town.

There are 1,346 unique addresses in her town with numbers ranging from zero to five children.

The results of 50 randomly generated households are shown below.

Children in 50 Households

Number of Children Number of Households

0 5

1 11

2 13

3 10

4 9

5 2

Then the value of p and n will be

p = 11/50

n = 1346

Then the expected value will be

E(x) = (11/50) x 1346

E(x) = 296.12 ≈ 296

Then the correct option is C.

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

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Step-by-step explanation:

To verify the identity:

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open the parenthesis on the right-hand side of the equation at the numerator and the denominator

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(1-cosx)(1+cosx) = 1 - cos²x

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Hence we will replace 1- cos²x by sin²x

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Note that;

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3 years ago

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