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Rasek [7]
2 years ago
12

Find the standard equation for the circle having the given center and radius.

Mathematics
1 answer:
RoseWind [281]2 years ago
7 0

\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{0}{h}~~,~~\underset{0}{k})}\qquad \stackrel{radius}{\underset{7}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - 0 ~~ )^2 ~~ + ~~ ( ~~ y-0 ~~ )^2~~ = ~~7^2\implies x^2+y^2=49

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6th grade math help me please ! :))
Stells [14]

Answer:

1,825 days

Step-by-step explanation:

730 / 2 = 365 (one year, or the number of days a single revolution around the sun takes)

Now just multiply by 5

[365 · 5 = 1,825], thus 1,825 days are the duration of 5 revolutions.

The problem could also be initially expressed as:

x = (720/2) · (5) with x representing the missing value

6 0
3 years ago
Using the numbers 3, 4, 5, and 7 create the smallest fraction and the largest fraction.(Please explain the steps)
luda_lava [24]

Answer:

largest: 7/3 smallest: 3/7

Step-by-step explanation:

the answer kinda explains the question on its own, but all it really is, is put largest on the smallest, or put the smallest an the largest.

5 0
3 years ago
Ples help A square is a rectangle. always sometimes never
MakcuM [25]

By definition, a rectangle is:

Any four sided polygon (quadrilateral) that contains four right angles.

By extension, a square is:

Any rectangle where all sides are of the same, or equal, length.

<h3>So yes, a square is always a rectangle.</h3>
6 0
3 years ago
Read 2 more answers
Factor completely:<br><br> <img src="https://tex.z-dn.net/?f=3x%5E3%2B21x%5E2%2B36x" id="TexFormula1" title="3x^3+21x^2+36x" alt
guajiro [1.7K]
To factor, you can first treat it like a single bracket and find the common factor. In this case, the common factor is 3x, so you get
3x(x² + 7x + 12)
Now you can factor the bracket normally, by finding factors of 12 that add up to make 7. The factors would be 3 and 4, so the bracket becomes (x + 3)(x + 4).
This leaves your final answer as
3x(x + 3)(x + 4)

I hope this helps!
5 0
3 years ago
Suppose that the function f is defined. , for all real numbers, as follows.
aivan3 [116]

Answer:   <em>The values of......</em>

<em>f(-5)=\frac{9}{4}\\ \\ f(-2)= -1\\ \\ f(4)=0</em>

Step-by-step explanation:

Given function is:   \left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.

For f(-5),  the value of x is -5, which is not equal to -2.

So,  f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}

For f(-2),  the value of x is -2.

So,  f(-2)= -1

For f(4),  the value of x is 4, which is not equal to -2.

So,  f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0

5 0
3 years ago
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