Question

there are 6 people in a raffle drawing. two raffle winners each wing gift cards . each gift card is the same. how many ways are there to choose the winners? decide if the situation involves a permutation or a combination , and then find the number of ways to choose the winners

Answer 1

Answer:

The combination is 15

Step-by-step explanation:

There are 6 people in a raffle drawing. two raffle winners each wing gift cards . each gift card is the same.

Lets call the winners Winner 1, Winner 2. According to the given statement each gift card is same, thus any permutation of these two winners are  equivalent.This tells us that the order of winners does not matter and the situation involves a combination.

Now we have to calculate the combination of 2 winners from 6 people.

nCm = m!/n!(m-n)!

where m = 6

n = 2

2C6 = 6!/2!(6-2)!

2C6 = 6!/2!(4)!

2C6 = 6*5*4*3*2*1/2*1*4*3*2*1

2C6= 6*5/2*1

2C6=30/2

2C6 = 15

Thus the combination is 15....