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MissTica
4 years ago
8

there are 6 people in a raffle drawing. two raffle winners each wing gift cards . each gift card is the same. how many ways are

there to choose the winners? decide if the situation involves a permutation or a combination , and then find the number of ways to choose the winners
Mathematics
1 answer:
Morgarella [4.7K]4 years ago
3 0

Answer:

The combination is 15

Step-by-step explanation:

There are 6 people in a raffle drawing. two raffle winners each wing gift cards . each gift card is the same.

Lets call the winners Winner 1, Winner 2. According to the given statement each gift card is same, thus any permutation of these two winners are  equivalent.This tells us that the order of winners does not matter and the situation involves a combination.

Now we have to calculate the combination of 2 winners from 6 people.

nCm = m!/n!(m-n)!

where m = 6

n = 2

2C6 = 6!/2!(6-2)!

2C6 = 6!/2!(4)!

2C6 = 6*5*4*3*2*1/2*1*4*3*2*1

2C6= 6*5/2*1

2C6=30/2

2C6 = 15

Thus the combination is 15....

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<u>Answer:</u>

2

<u>Step-by-step explanation:</u>

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⇒ (\frac{4^{\frac{6}{4}  }}{4^{\frac{1}{2} }})^{\frac{1}{2} }

• Dividing two numbers with same bases is the same as subtracting their powers:

∴  (\frac{4^{\frac{6}{4}  }}{4^{\frac{1}{2} }})^{\frac{1}{2} }

⇒ (4^{{\frac{6}{4} - \frac{1}{2} }})^{\frac{1}{2} }

⇒  (4^{1})^{\frac{1}{2} }

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2 years ago
The student council sold 300 tickets for a basketball game. An adult ticket costs $3.00 and a student ticket costs $1.00. Ticket
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Komok [63]

Answer:

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Step-by-step explanation:

given equation,

x + y = 17     ........(1)

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writing in matrix form

A X = B

\begin{bmatrix}1 &1 \\ 9 &-1 \end{bmatrix} \begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}17\\73 \end{bmatrix}

using augamented matrix A|B

\begin{bmatrix}1 &1& 17\\ 9 & -1 & 73\end{bmatrix}

using row transformation

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now

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