Answer:
7/20
Step-by-step explanation:
I did the work but Im not sure if this is right i just need points to ask my question. But what i did was i did 14 divided by 4=3.5, then moved the decimal in front of the 3 to make .35 then turned that into a fraction 7/20. AGAIN I DONT KNOW IF ITS RIGHT DONT BLAME ME IF ITS NOT
Utilizando proporciones, hay que el pick-up más grande carga 5250 kg.
- Este problema se resuelve por proporciones, por médio de una regla de três.
El peso que cargan tres pick-ups están en la razón de 2:6:7
- 2 + 6 + 7 = 15.
- O sea, el pick-up menor carga
de el total, que es equivalente a 1500 kg. - El pick-up más grande carga
de el total, que es equivalente a x kg.
La regla de três es:
- 1500 kg
- x kg
Aplicando multiplicación cruzada:
El pick-up más grande carga 5250 kg.
Un problema similar es dado en brainly.com/question/24615636
For the first question, x = 4
Let us assume the larger number = x
Let us assume the smaller number = y
Then
x + y = 3 3/4
x + y = 15/4
And
x/3 = (2y/3) + 1/2
x = [3 * (2y/3)] + (3/2)
= 2y + (3/2)
Now putting the value of x from the second equation to the first , we get
x + y = 15/4
2y + (3/2) + y = 15/4
3y = (15/4) - (3/2)
3y = (15 - 6)/4
3y * 4 = 9
12y = 9
y = 9/12
= 3/4
Now putting the value of y in the first equation, we get
x + y = 15/4
x + (3/4) = (15/4)
x = (15/4) - (3/4)
= (15 - 3)/4
= 12/4
= 3
So the value of x or the larger number is 3 and the value of y or the smaller number is 3/4.
