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Eduardwww [97]
3 years ago
12

If g(x) = 2x- x + 5, then g (2)=

Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0
2(2)-(2)+5=7
g(2) equals 7
Andreyy893 years ago
5 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

(2) literally means to plug in 2 for x, so: 

<span>g(2)=2(2)-(2)+5 </span>
<span>g(2)=4-2+5 </span>
<span>g(2)=7</span>
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vfiekz [6]

Answer:

4

Step-by-step explanation:

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3 years ago
Please help<br><br>4(4+2x)=x(x+5)​
lapo4ka [179]

Answer:

EF = 6

Step-by-step explanation:

Using the secant- secant power theorem, that is

GF × GE = GH × GS

4(4 + 2x) = 5(5 + x) ← distribute both sides

16 + 8x = 25 + 5x ( subtract 5x from both sides )

16 + 3x = 25 ( subtract 16 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Then

EF = 2x = 2 × 3 = 6

3 0
3 years ago
On December 1, Jasmin Ernst organized Ernst Consulting. On December 3, the owner contributed $85,360 in assets in exchange for i
blagie [28]

The income statement illustrates that the net income will be $3530.

<h3>How to calculate the income statement?</h3>

The income statement will be:

<u>Revenue</u>

Consulting revenue 18350

<u>Expenses</u>

Miscellaneous expenses 720

Rent expense 4820

Salaries expense 8370

Telephone expenses 910

Total expenses 14820

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6 0
2 years ago
Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)
jeyben [28]

Answer:

The vertex: (\frac{3}{4},-\frac{41}{4} )

The vertical intercept is: y=-8

The coordinates of the two intercepts of the parabola are (\frac{3+\sqrt{41} }{4} , 0) and (\frac{3-\sqrt{41} }{4} , 0)

Step-by-step explanation:

To find the vertex of the parabola 4x^2-6x-8 you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em>a=4, b=-6, \:and \:c=-8</em>

2. You can apply this formula to find x-coordinate of the vertex

x=-\frac{b}{2a}, so

x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c)

f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

\mathrm{Add\:}8\mathrm{\:to\:both\:sides}

x^2-6x-8+8=0+8

\mathrm{Simplify}

4x^2-6x=8

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2

\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2

x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}

\left(x-\frac{3}{4}\right)^2=\frac{41}{16}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}

4 0
3 years ago
PLEASE HELP ME IM BEING TIMEDD
JulsSmile [24]
10 rows because that's right
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3 years ago
Read 2 more answers
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