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Nastasia [14]
1 year ago
12

Which of the following describes the function shown in the table below? x y -4 16 -1 2 2 0.25 4 0.0625 5 0.03125 exponential, th

ere is a continual rate of growth exponential, there is a continual rate of decay or decrease quadratic, there is a second degree change in the y-values quadratic, there is a constant difference between consecutive y-values
Mathematics
1 answer:
wolverine [178]1 year ago
3 0

A statement which best describes the function shown in the table is: B. exponential, there is a continual rate of decay or decrease.

<h3>What is an exponential function?</h3>

An exponential function is a mathematical function whose numerical values (numerals) are generated by a constant that is raised to the power of an argument.

<u>Given the following table:</u>

X : -4        -1        2            4              5

Y :  16        2       0.25   0.0625    0.03125

Next, we would calculate the rate of decay for the y-values:

16/2 = 2/0.25 = 0.25/0.0625 = 0.0625/0.03125 = 8

<u>Rule:</u> The y-values constantly decreases by 1/4 or 0.25 of the previous number.

In conclusion, we can logically deduce that the function shown in the table is exponential, there is a continual rate of decay or decrease.

Read more on exponential functions here: brainly.com/question/12940982

#SPJ1

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4x + y = h

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-4y - 4h = x

Cheers!
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Marcos purchased a sail boat for $56,900. He anticipates each year the boat will decrease in value by 8.1% from the previous yea
Varvara68 [4.7K]

Answer: 56,900\left( 0.919\right)^x

Step-by-step explanation:

Given

Marcos purchased a sailboat for \$56,900

Each year the boat will decrease in value by 8.1\%

After 1 year it is

\Rightarrow 56,900-56,900\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\\

after another year it becomes

\Rightarrow 56,900\left( 1-0.081\right)-56,900\left( 1-0.081\right)\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\cdot \left( 1-0.081\right)\\\Rightarrow 56,900\left( 1-0.081\right)^2

After x years it is

\Rightarrow 56,900\left( 1-0.081\right)^x

\Rightarrow 56,900\left( 0.919\right)^x

5 0
2 years ago
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y)^6 are _____.
Kryger [21]
Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
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 Therefore, the coefficients of the expansion are given by:
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The students in Mr. Wilson's Physics class are making golf ball catapults. The
Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is 0 \leq x \leq 48.6\ ft and the range is 0 \leq y \leq 8.3\ ft

Step-by-step explanation:

we have

y=-0.014x^{2} +0.68x

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's  distance from the catapult in feet

y is the flight of the balls in feet

Part a)  How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-0.014x^{2} +0.68x=0

so

a=-0.014\\b=0.68\\c=0

substitute in the formula

x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}

x=\frac{-0.68(+/-)0.68} {(-0.028)}

x=\frac{-0.68(+)0.68} {(-0.028)}=0

x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

y=-0.014x^{2} +0.68x

Find out the derivative and equate to zero

0=-0.028x +0.68

Solve for x

0.028x=0.68

x=24.3

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint  between the x-intercepts

x=(0+48.6)/2=24.3\ ft

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

y=-0.014(24.3)^{2} +0.68(24.3)

y=8.3\ ft

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A  reasonable domain is the distance between the two x-intercepts

so

0 \leq x \leq 48.6\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A  reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

0 \leq y \leq 8.3\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0
2 years ago
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